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1 year ago

11

0.403 divided by 100 what is the quotient

1 answer:

Alja [10]1 year ago

4 0

Answer: 0.403 / 100 = 0.00403

Hope this helps ♥️

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What is the length of line segment KJ?

Karolina [17]

Please consider the attached file.

We can see that triangle JKM is a right triangle, with right angle at M. Segment KM is 6 units and segment MJ is 3 units. We can also see that KJ is hypotenuse of right triangle.

We will use Pythagoras theorem to solve for KJ as:

$KJ^2=KM^2+MJ^2$

$KJ^2=6^2+3^2$

$KJ^2=36+9$

$KJ^2=45$

Now we will take positive square root on both sides:

$\sqrt{KJ^2}=\sqrt{45}$

$KJ=\sqrt{9\cdot 5}$

$KJ=3\sqrt{5}$

Therefore, the length of line segment KJ is $3\sqrt{5}$ and option D is the correct choice.

5 0

3 years ago

Write an expression to represent "triple the<br> quotient of a number and three."

Furkat [3]

Answer:

3n/3 or 3n÷3

Step-by-step explanation:

since it says triple the quotient of a <u>number</u>, we can use the number n.

To find the quotient means to divide and it's going to be by that numer.....n....... trippled (3)

put them all together and you get 3n/3

4 0

2 years ago

Six different second-year medical students at Bellevue Hospital measured the blood pressure of the same person. The systolic re

Yanka [14]

Answer:

$Range=14$

$\sigma^2 =32.4$

$\sigma = 5 .7$

The standard deviation will remain unchanged.

Step-by-step explanation:

Given

$Data: 136, 129, 141, 139, 138, 127$

Solving (a): The range

This is calculated as:

$Range = Highest - Least$

Where:

$Highest = 141; Least = 127$

So:

$Range=141-127$

$Range=14$

Solving (b): The variance

First, we calculate the mean

$\bar x = \frac{1}{n} \sum x$

$\bar x = \frac{1}{6} (136+ 129+ 141+ 139+ 138+ 127)$

$\bar x = \frac{1}{6} *810$

$\bar x = 135$

The variance is calculated as:

$\sigma^2 =\frac{1}{n-1}\sum(x - \bar x)^2$

So, we have:

$\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]$

$\sigma^2 =\frac{1}{5}*[162]$

$\sigma^2 =32.4$

Solving (c): The standard deviation

This is calculated as:

$\sigma = \sqrt {\sigma^2 }$

$\sigma = \sqrt {32.4}$

$\sigma = 5 .7$ --- approximately

Solving (d): With the stated condition, the standard deviation will remain unchanged.

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2 years ago

Someone please helpp meeeee?!?!!

Marianna [84]

Answer:

Goodluck I had this before and couldn't get it

8 0

2 years ago

Read 2 more answers

Which congruence theorems can be used to prove EFG congruent to JHG

MatroZZZ [7]

SAS you have two pairs of parallel sides

you have another pair of side congruent to one another

and angle G is the same to itself.

3 0

2 years ago