1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
White raven [17]
3 years ago
5

a studernt has pased 60 percent of 20 quizzes he has written so far successfully. if the student 50 quizzes during the year, and

passes 80 percent of the remaning quizzes successfully what is the precent of all the successful quizzess for the entire year
Mathematics
1 answer:
faust18 [17]3 years ago
5 0

Answer:

72%

Step-by-step explanation:

There are a total of 50 quizzes in the year

From the first 20, the student passes 60%. This makes a total of

\frac{60}{100} (20) = 12

12 passes

Out of the remaining 30 quizzes the student passes in 80% of them. This makes a total of

\frac{80}{100} (30) = 12

24 passes

Adding the two values

12 + 24 = 36

The student passes 36 quizzes out of 50.

We convert this to a percentage

\frac{36}{50} (100) = 72%

You might be interested in
What are four consecutive integers whose sum is 682
Fynjy0 [20]
X, x+1, x+2, x+3 - four consecutive integers

x+x+1+x+2+x+3=682 \\
4x+6=682 \ \ \ |-6 \\
4x=676 \ \ \ |\div 4 \\
x=169 \\ \\
x+1=169+1=170 \\
x+2=169+2=171 \\
x+3=169+3=172

The integers are 169, 170, 171 and 172.
7 0
4 years ago
Read 2 more answers
What’s another way to write 6+6+6+6?
vredina [299]
6 times 4
3+3+3+3+3+3+3+3
4 0
3 years ago
Read 2 more answers
Find the probability of rolling a 4 or less on the first die, and a 5 or less on the second die
bearhunter [10]

Answer:

first dice-4/6

second dice-5/6

Step-by-step explanation:

if you have six possible outcomes for the first dice and you want it to roll 1 thru 4 then you have a four out of six chance and you have a 5 out of six chance for the second dice

3 0
3 years ago
A local aquarium purchased a new turtle tank for their giant turtle exhibit. What is the volume of the turtle tank. 15 yd, 12yd,
slavikrds [6]

Answer:

1440 yd³

1200 yd³

Step-by-step explanation:

A local aquarium purchased a new turtle tank for their giant turtle exhibit  for their giant turtle exhibit.

By using the dimensions 15yd by 12yd by 8yd and the shape of the tank is cubooid

We can determine volume by using the formula i.e

V = (Length) × (Width) × (Height),

then the volume of the tank will be

V = 15 × 12 × 8 =

V=1440 yd³.

Now , by using dimensions 15 yd by 8 yd by 10 yd

The volume will be,

V = 15 × 8 × 10 = 1200yd³

6 0
3 years ago
In remodeling a house an architect finds that by adding the same amount to each dimension of a 15ft by 19ft rectangular room, th
earnstyle [38]

Answer:

Step-by-step explanation:

new length=15+x

width=19+x

then area=(15+x)×(19+x)=285+15x+19x+x²=x²+34x+285 ft²

original area=15×19=285 ft²

then 285+98=x²+34x+285

or

x²+34x-98=0

x²+34x+17²=98+17²

(x+17)²=98+289=387

x+17=√387=3√43

x=3√43-17 ft

8 0
3 years ago
Other questions:
  • A line has a slope of - 2/3 and passes through the point (-3, 8) what is the equation of the line
    5·1 answer
  • 39477 round to the nearest 1000
    5·1 answer
  • The temperature inside the lab refrigerator is at most 35 Fahrenheit used to represent the temperature in fahrenheit of the refr
    8·1 answer
  • Enter your answer and show all the steps that you use to solve this problem in the space provided
    15·1 answer
  • Sarah earned 5 points for every 7 books she read. So if she read 1 book she would have earned ____ of a point.
    7·1 answer
  • Find x and y in the figures below
    8·1 answer
  • Please help me with this
    12·1 answer
  • Can someone please help me with this question it is a hard question for me to answer​
    8·1 answer
  • A student scored 80 and 93 on her first two quizzes. Write and solve a compound inequality to find the
    15·1 answer
  • help me pleaseee asappp solving systems of equations
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!