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madam [21]
2 years ago
10

HELP FAST PLEASE! If a reaction takes place and the theoretical yield is 73 g and the actual yield is 62 g, calculate the percen

t yield.
Choices:

A. 76%

B. 1.16%

C. 116%

D. 85%
Chemistry
1 answer:
allsm [11]2 years ago
6 0

Answer:

A

Explanation:

I think it's A. There are good answer for A.

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What are the missing coefficients for H3PO4 + HCl = PCl5 + H2o
grigory [225]

Answer:

H3PO4 + 5 HCl → PCl5 + 4 H2O

Explanation:

The given equation is

H3PO4 + HCl = PCl5 + H2O

The above chemical equation has one P atom on both the sides, hence phosphorus is balanced

There are 5 Cl on the RHS but only one Cl on the LHS. On balancing the chlorine, we get -

H3PO4 + 5HCl = PCl5 + H2O

Now, there are 8 hydrogen atom on the LHS but only two on the RHS. On balancing the hydrogen on both the sides, the new equation become

H3PO4 + 5HCl = PCl5 + 4H2O

Let us check for oxygen

Oxygen on LHS = 4 and oxygen on RHS = 4

Thus, the balanced equation is H3PO4 + 5HCl = PCl5 + 4H2O

7 0
3 years ago
A sample of gas in a sealed container (fixed volume) is heated from room temperature to 80.0°C.
inna [77]
Hello!

A) When the temperature inside the container increases, the pressure inside the container increases as well. 

An example for that is when you have an aerosol can and start heating it. The pressure of the gas inside the aerosol can will start to increase, and that would lead to the exploding of the can if heating is kept for too long. Bombs work on this principle too: The heat from the violent chemical reaction inside the closed compartment increase the pressure of the gases until the fragments are ejected at high velocities. 

B) The effect of temperature on the pressure of a gas illustrates Gay-Lussac's Law.

This law was formulated by the famous French chemist that gives it its name. It relates the expansion of a gas with the increase in temperature when the volume is left constant. The Gay-Lussac's Law can be expressed as follows, for the case of this exercise:

\frac{P1}{T1}= \frac{P2}{T2} \\ \\ P2= \frac{P1}{T1}*T2=P1* \frac{80 degC}{25degC}= P1*3,2

You can see that the factor that is multiplying P1 is higher than 1 for the case of heating from 25 °C to 80 °C, so the pressure will increase.

C) At a molecular level, when the temperature is raised the kinetic energy of the molecules inside the container will increase. This increase in the kinetic energy will cause the molecules to move faster, and to hit the walls of the container more often. This causes an increase in the pressure inside the container because there more hits means more force on the walls of the container, and that is the definition of pressure. 

Have a nice day!
8 0
4 years ago
PLEASE HELP ASAP. I WILL MARK BRAINLIEST!!!
iris [78.8K]

I Cant Answer your question but maybe this will help

Volume Changes for Gases

Particles in a gas have more freedom of movement than they do in a liquid. According to the ideal gas law, the pressure (P) and volume (V) of a gas are mutually dependent on temperature (T) and the number of moles of gas present (n). The ideal gas equation is PV = nRT, where R is a constant known as the ideal gas constant. In SI (metric) units, the value of this constant is 8.314 joules ÷ mole - degree K.

Pressure is constant: Rearranging this equation to isolate volume, you get: V = nRT ÷ P, and if you keep the pressure and number of moles constant, you have a direct relationship between volume and temperature: ∆V = nR∆T ÷ P, where ∆V is change in volume and ∆T is change in temperature. If you start from an initial temperature T0 and pressure V0 and want to know the volume at a new temperature T1 the equation becomes:

V1 = [n • R • (T1 - T0) ÷ P] +V0

Temperature is constant: If you keep the temperature constant and allow pressure to change, this equation gives you a direct relationship between volume and pressure:

V1 = [n • R • T ÷ (P1 - P0)] + V0

Notice that the volume is larger if T1 is larger than T0 but smaller if P1 is larger than P0.

Pressure and temperature both vary: When both temperature and pressure vary, the the equation becomes:

V1 = n • R • (T1 - T0) ÷ (P1 - P0) + V0

Plug in the values for initial and final temperature and pressure and the value for initial volume to find the new volume.

6 0
3 years ago
Read 2 more answers
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.10 g of ethane is
puteri [66]

Answer:

Ethane is the limiting reactant, so no mass of ethane will be left over by the chemical reaction. All the mass will react, the 2.1 grams of ethane.

Explanation:

First of all, we need to determine the reaction and the limiting reactant to work with the stoichiometry.

The equation is: 2C₂H₆ + 7O₂ →  4CO₂ + 6H₂O

We define the moles of the reactants:

2.10 g / 30 g/mol = 0.07 moles of ethane

12 g / 32 g/mol = 0.375 moles of oxygen

To determine the limiting reactant, we start with oxygen:

7 moles of O₂ can react with 2 moles of ethane

Then, 0.375 moles of O₂ will react with (0.375 . 2) / 7= 1.31 moles of ethane.

We do not have enough ethane, just only 0.07 moles to react.

Ethane is the limiting reactant, so no mass of ethane will be left over by the chemical reaction. All the mass will react, the 2.1 grams of ethane.

7 0
3 years ago
Read 2 more answers
Covers top layer of leaf, is water-repellent and prevents water loss
denpristay [2]
If the water is on top of the leaf and doesn't soak in then it is water repellent 
4 0
4 years ago
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