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2 years ago

10

HELP FAST PLEASE! If a reaction takes place and the theoretical yield is 73 g and the actual yield is 62 g, calculate the percen

t yield.
Choices:

A. 76%

B. 1.16%

C. 116%

D. 85%

1 answer:

allsm [11]2 years ago

6 0

Answer:

A

Explanation:

I think it's A. There are good answer for A.

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Choose whether the statements about oil sands are true or false. The viscosity of bitumen is about 100 times greater than the vi

Alexxx [7]

The First 2 statements stated above were false whereas the third one is a true statement.

Explanation:

The viscosity of bitumen is about 100 times greater than the viscosity of water - False

Reason - The viscosity of bitumen is about not 100 times greater than the viscosity of water, it is actually 100, 000 times greater.

Oil from oil sand deposits is only obtained by first heating the sands at high temperatures is False.

Reason- Oil from oil sand deposits is not obtained by first heating the sands at high temperatures but by using steams

Oil sands contain sand, water, and light crude oil is true.

6 0

4 years ago

Maybe someone can help me out with this or give me the equation to find mols/liters - thanks to if you can help, here's the ques

zvonat [6]

Answer :The correct answers are :

Concentration in one can soup : Table salt = 6.12 $\frac{mol}{L}$

Table sugar = 5.84 $\frac{mol}{L}$

Concentration in one bowl Soup : Table salt = 3.82 $\frac{mol}{L}$

Table sugar = 3.65 $\frac{mol}{L}$

Concentration : It is quantity to measure a solution . It can be defined as abundance of constituents per volume of solution . The most used concentration is molar concentration .

Molar concentration is defined as mole of solute present in volume of solution . The unit of concentration is $\frac{mol}{L}$ . It is expressed as :

$Concentration ( \frac{mol}{L} ) = \frac{mole of solute (mol)}{Volume of solution (L)}$

Concentration in one can of soup (Volume = 250 mL )

Volume of one can soup = 250 mL . Converting it from mL to L as :

(1 L = 1000mL)

$Volume of one can soup = \frac{250 mL}{1000mL} * 1 L = 0.250 L$

A) Concentration of table salt :

Following are the steps to find out molar concentration :

Step 1 : Find mass of solute :

Since mass of solute is not given , so we take solubility of NaCL in 1 L of water . Solubility is maximum amount of NaCL that can be dissolved in 1 L water at room temperature . From image , we can say that 359 g of NaCL can be dissolved ideally in 1 L of water .

Since volume of solution is 0.250 L , so mass of salt in 0.250 L can be found :

Mass of NaCL in 1 L = 359 g

Mass of NaCL in 0.250 L of water = 359 g * 0.250 L

Mass of NaCL in 0.250 L = 89.75 g

Step 2 : Convert mass of solute to its mole

Mole can be calculate from mass as :

$Mole (mol) = \frac{given mass (g) }{molar mass \frac{g}{mol}}$

Molar mass of Table salt (given ) = 58.44 $\frac{g}{mol}$

plugging value of mass and molar mass in mole formula :

$Mole = \frac{89.75 g }{58.44 \frac{g}{mol}}$

Mole of Table salt = 1.53 mol

Step 3 : To find concentration .

Mole of solute = 1.53 mol

Volume of solution ( one can of soup ) = 0.250 L

Plugging these values in Concentration formula :

$Concentration = \frac{1.53 mol}{0.250 L}$

Concentration of Table salt in one can soup = 6.12 $\frac{mol}{L}$

B) Concentration of Table sugar :

Following steps can be used :

Step 1: To find mass of Table sugar

Since mass of sugar is not given , so solubility of sugar will be considered . From image solubility is 2000 g in 1 L of water .

Since volume of one cup soup is 0.250 L , so mass of Sugar in 0.250 L of solution =

Mass of sugar in 1 L of water = 2000 g

Mass of sugar in 0.250 L of solution = 2000 g* 0.250 L

Hence , mass of Sugar in 0.250 L of solution = 500 g

Step 2 : To convert mass of sugar to its mole

Mass can be converted to mole using same formula. Plugging value in mole formula :

$Mole of sugar = \frac{500 g}{342.3 \frac{g}{mol}}$

Mole of sugar = 1.46 mol

Step 3 : To find concentration of Sugar :

Mole of sugar = 1.46 mol

Volume of solution = 0.250 L

Plugging these values in concentration formula :

$Concentration = \frac{1.46 mol}{0.250 L} = 5.84 \frac{mol}{L}$

-----------------------------------------------------------------------------------------------------------

Concentration in one bowl of soup :

Volume of one bowl of soup = 150 mL water + 250 mL of one can soup

= 400 mL

Converting mL to L : ( 1 L = 1000mL )

$Volume of solution = \frac{400 mL}{1000mL} * 1 L$

Volume of solution = 0.400 L

A) Concentration of Table salt :

Similar steps will be used :

Step 1: T find mass of Table salt

Again solubility will be used , which is =359 g in 1 L .Since 150 mL water is added which had no salt . hence all the salt was present in 250 mL one can soup , so mass of salt present in one can soup will be used .

Mass of Table salt = 89.75 g

Step 2: To convert mass to mole

Mass can be converted using mole formula .

Mole of Table salt = 1.53 mol ( calculated above )

Step 3: To find concentration

Mole of Table salt = 1.53 mol

Volume of one bowl soup = 0.400 L

Plugging these values in Concentration formula as:

$Concentration = \frac{1.53 mol}{0.400 L }$

Concentration of Table salt in one bowl soup = 3.82 $\frac{mol}{L}$

B) Concentration of Table sugar :

Step 1 : To find mass of Table sugar

Mass of sugar in 0.400 L will be same as that of mass of sugar present in 0.250 L since water had no sugar .

Mass of Table sugar = 500 g

Step 2 : To convert mass to mole

Mole can be calculated using mole formula ( as calculated above for one can soup )

Mole of Table sugar = 1.46 mol

Step 3: To find concentration

Mole of Table sugar (solute ) = 1.46 mol

Volume of one bowl soup = 0.400 L

Plugging these values in concentration formula :

$Concentration = \frac{1.46 mol}{0.400 L}$

Concentration of Table sugar in one bowl soup = 3.65 $\frac{mol}{L}$

----------------------------------------------------------------------------------------

Also Note :You have marked Table sugar as Ionic which is incorrect .Table sugar is covalent as it has all non metals .

8 0

4 years ago

Help would be appreciated!

aivan3 [116]

Answer is A) Al4C3 + 3H2O -> CH4 + 4Al(OH)3

One the left side there are 3 carbon atoms, or moles of carbon, and on the write side there is only one.

In order to solve these problems, count the number of atoms on each side and make sure that for each element, the number of atoms are equal.

For example, for the last problem, we have 1 zinc atom on each sidde, two hydrogen atoms, and two chlorine atoms.

8 0

3 years ago

Something that does not have the ability to react is considered

nasty-shy [4]

Something that does not have the ability to react is considered inert. <span> In chemistry, the term </span>inert<span> is used to describe a substance that is not </span>chemically<span> reactive. Hope this answers the question. Have a nice day.</span>

4 0

4 years ago

4.62 ) (a) Calculate the molarity of a solution made by dissolving 12.5 grams of Na2CrO4 in enough water to form exactly 750 mL

Gelneren [198K]

Answer:

a. [Na₂CrO₄] = 0.10 M

b. 0.017 moles of KBr

Explanation:

Molarity means a sort of concentration which indicates the moles of solute over 1L of solution.

We determine the moles of solute: 12.5 g / 162g/mol = 0.0771 moles

We convert the volume of solution from mL to L = 750 mL . 1L/1000mL = 0.750L

Molarity (mol/L) → 0.0771 mol / 0.750L = 0.10 M

b. In order to determine the moles of solute, with the molarity of solution and the volume we assume:

Molarity = moles of solute /volume of solution

Then, Molarity . Volume of solution (L) = moles of solute

We convert the volume of solution from mL to L = 150 mL . 1L/1000mL = 0.150L

0.112 mol/L . 0.150L = Moles of solute → 0.017 moles of KBr

5 0

4 years ago

Read 2 more answers