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2 years ago

In your own words, please describe the difference between a complete ionic equation and a net ionic equation.

Chemistry

1 answer:

beks73 [17]2 years ago

6 0

Explanation:

In the molecular equation for a reaction, all of the reactants and products are represented as neutral molecules (even soluble ionic compounds and strong acids). In the complete ionic equation, soluble ionic compounds and strong acids are rewritten as dissociated ions.

The net ionic equation is a chemical equation for a reaction that lists only those species participating in the reaction. The net ionic equation is commonly used in acid-base neutralization reactions, double displacement reactions, and redox reactions.

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1. Two parallel normal faults form.

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2 years ago

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What is the correct equilibrium constant

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Answer:[co2][CF4]

[COF2]^2

Explanation:

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3 years ago

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How many moles of Chromium is in 4.41 ×10^24 atoms

zalisa [80]

7.32 moles of Chromium is present in 4.41 × 10²⁴ atoms.

<h3>How to find the number of moles ?</h3>

Number of moles = $\frac{\text{Given number of atoms}}{\text{Avogadro's Number}}$

<h3>What is Avogadro's Number ?</h3>

Avogadro's number is the number of particles in one mole of substance. 6.022 × 10²³ is known as Avogadro's Constant / Avogadro's Number.

Avogadro's Number = 6.022 × 10²³

Now put the values in above formula we get

Number of moles = $\frac{\text{Given number of atoms}}{\text{Avogadro's Number}}$

= $\frac{4.41 \times 10^{24}}{6.022 \times 10^{23}}$

= 7.32 moles

Thus from the above conclusion we can say that 7.32 moles of Chromium is present in 4.41 × 10²⁴ atoms.

Learn more about the Avogadro's Number here: brainly.com/question/1581342

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3 0

1 year ago

I’m struggling with dimensional analysis in chemistry! Will someone please help me with .74 Kcal/min to cal/sec ? Explain and gi

valina [46]

Answer:

12.33 cal/sec

Explanation:

As we know,

1 Kcal = 1000 cal

So,

0.74 Kcal = X cal

Solving for X,

X = (0.74 Kcal × 1000 cal) ÷ 1 Kcal

X = 740 cal

Also we know that,

1 Minute = 60 Seconds

Therefore, in order to derive cal/sec unit replace 0.74 Kcal by 740 cal and 1 min by 60 sec in given unit as,

= 740 cal / 60 sec

= 12.33 cal/sec

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3 years ago

Pls help me out with this question!

jeka94

At STP, copper (Cu) would be the only substance here that will exist in the solid state.

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2 years ago