After 160 years, the activity level of the sample will be 0.5 curies.
<h3>What is half-life?</h3>
Half life of any radioactive waste is the half decay of that product.
The formula is 
Where, λ is 4 cruies
λ1 is 0.5 cruies
b = 40 years
Putting the values in the equation

Thus, the correct option is 160 years.
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False, carbon is an allotrope that can be in the forms of graphite, diamond etc
Answer:
(1) Cl₂ is the limiting reactant.
(2) 8.18 g
Explanation:
- 2Na(s) + Cl₂(g) → 2NaCl(s)
First we <u>convert the given masses of reactants into moles</u>, using their <em>respective molar masses</em>:
- Na ⇒ 12.0 g ÷ 23 g/mol = 0.522 mol Na
- Cl₂ ⇒ 5.00 g ÷ 70.9 g/mol = 0.070 mol Cl₂
0.070 moles of Cl₂ would react completely with (2 * 0.070) 0.14 moles of Na. There are more Na moles than that, so Na is the reactant in excess while Cl₂ is the limiting reactant.
Then we <u>calculate how many moles of NaCl are formed</u>, <em>using the limiting reactant</em>:
- 0.070 mol Cl₂ *
= 0.14 mol NaCl
Finally we <u>convert NaCl moles into grams</u>:
- 0.14 mol NaCl * 58.44 g/mol = 8.18 g
Answer:
0.062mol
Explanation:
Using ideal gas law as follows;
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821Latm/molK)
T = temperature (K)
Based on the information provided;
P = 152 Kpa = 152/101 = 1.50atm
V = 0.97L
n = ?
T = 12°C = 12 + 273 = 285K
Using PV = nRT
n = PV/RT
n = (1.5 × 0.97) ÷ (0.0821 × 285)
n = 1.455 ÷ 23.39
n = 0.062mol
This equation is impossible. NaSO4 is non-existent. Did you mean Na2SO4?