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Vera_Pavlovna [14]
3 years ago
12

PLEASE HELP ASAP. I WILL MARK BRAINLIEST!!!

Chemistry
2 answers:
iris [78.8K]3 years ago
6 0

I Cant Answer your question but maybe this will help

Volume Changes for Gases

Particles in a gas have more freedom of movement than they do in a liquid. According to the ideal gas law, the pressure (P) and volume (V) of a gas are mutually dependent on temperature (T) and the number of moles of gas present (n). The ideal gas equation is PV = nRT, where R is a constant known as the ideal gas constant. In SI (metric) units, the value of this constant is 8.314 joules ÷ mole - degree K.

Pressure is constant: Rearranging this equation to isolate volume, you get: V = nRT ÷ P, and if you keep the pressure and number of moles constant, you have a direct relationship between volume and temperature: ∆V = nR∆T ÷ P, where ∆V is change in volume and ∆T is change in temperature. If you start from an initial temperature T0 and pressure V0 and want to know the volume at a new temperature T1 the equation becomes:

V1 = [n • R • (T1 - T0) ÷ P] +V0

Temperature is constant: If you keep the temperature constant and allow pressure to change, this equation gives you a direct relationship between volume and pressure:

V1 = [n • R • T ÷ (P1 - P0)] + V0

Notice that the volume is larger if T1 is larger than T0 but smaller if P1 is larger than P0.

Pressure and temperature both vary: When both temperature and pressure vary, the the equation becomes:

V1 = n • R • (T1 - T0) ÷ (P1 - P0) + V0

Plug in the values for initial and final temperature and pressure and the value for initial volume to find the new volume.

Kay [80]3 years ago
4 0

Answer:

1) If the volume of a container is increased, the temperature increases. 2) If the volume of a container is decreased, the temperature decreases. This means that the volume of a gas is directly proportional to its temperature. ... If the amount of gas in a container is decreased, the volume decreases

Explanation:

hope it helps you

❤ ❤ ❤ ❤ ❤

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Rina8888 [55]

The decomposition of Al2O3 to form pure aluminum (Al) along with the release of oxygen (O2) gas can be represented by the following chemical reaction:

2Al2O3 → 4Al + 3O2

Based on the reaction stoichiometry:

2 moles of aluminum oxide decomposes to form 4 moles of pure aluminum

Therefore, if 29.0 moles of aluminum is recovered, then the moles of aluminum oxide required will be:

= 29.0 moles Al * 2 moles Al2O3/4 moles Al

= 14.5 moles of Al2O3

4 0
4 years ago
Which of the following atoms has the same number of neutrons as 9Be?
xxMikexx [17]

Answer: -

¹⁰B

Explanation: -

For ⁹Be,

The atomic number is 4.

The Mass number is 9.

The number of neutrons = mass number - atomic number

= 9 - 4 = 5

For ⁹B,

The atomic number is 5.

The Mass number is 9.

The number of neutrons = mass number - atomic number

= 9-5 = 4

For ¹⁰B,

The atomic number is 5.

The Mass number is 10.

The number of neutrons = mass number - atomic number

= 10-5 = 5

For ¹⁰Be,

TThe atomic number is 4.

The Mass number is 10.

The number of neutrons = mass number - atomic number

= 10-4 = 6

For ¹²C,

The atomic number is 6.

The Mass number is 12.

The number of neutrons = mass number - atomic number

= 12-6 = 6

4 0
4 years ago
TRUE or FALSE: Any measurement that has been cubed is volume.
zmey [24]

Answer:

True

Explanation:

Volume is measured in "cubic" units. The volume of a figure is the number of cubes required to fill it completely, like blocks in a box. Volume of a cube = side times side times side. Since each side of a square is the same, it can simply be the length of one side cubed.

7 0
4 years ago
For the reaction, A(g) + B(g) => AB(g), the rate is 0.385 mol/L.s when the initial concentrations of both A and B are 2.00 mo
Tanya [424]

Answer : The rate for a reaction will be 0.14Ms^{-1}

Explanation :

The balanced equations will be:

A(g)+B(g)\rightarrow AB(g)

In this reaction, A and B are the reactants.

The rate law expression for the reaction is:

\text{Rate}=k[A]^2[B]^1

or,

\text{Rate}=k[A]^2[B]

Now, calculating the value of 'k' by using any expression.

\text{Rate}=k[A]^2[B]

0.385=k(2.00)^2(2.00)

k=0.0481M^{-2}s^{-1}

Now we have to calculate the initial rate for a reaction that starts with 1.48 M of reagent A and 1.32 M of reagents B.

\text{Rate}=k[A]^2[B]^0[C]^1

\text{Rate}=(0.0481)\times (1.48)^2(1.32)^1

\text{Rate}=0.14Ms^{-1}

Therefore, the rate for a reaction will be 0.14Ms^{-1}

7 0
4 years ago
What was the initial volume of gas if a new volume of 3.00 liters is obtained when the pressure is decreased from 3.00 atm to 1.
timurjin [86]

Answer:

1 L

Explanation:

V1=P2V2/P1

Checking this, it is correct because P and V at constant T has an inverse relationship.

- Hope that helps! Please let me know if you need further explanation.

4 0
3 years ago
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