Answer: the value for the associated test statistic is 1.2653
Step-by-step explanation:
Given that;
sample size one n₁ = 10
mean one x"₁ = 6.4
standard deviation one S₁ = 1.1
sample size two n₁ = 11
mean two x"₂ = 5.6
standard deviation one S₁ = 1.7
H₀ : μ₁ = μ₂
H₁ : μ₁ ≠ μ₂
Pooled Variance
sp = √( { [(n₁ - 1) × s₁² + (n₂ - 1) × s₂²] / (n₁ + n₂ - 2)} × (1/n₁ + 1/n₂))
we substitute
= √( { [(10 - 1) × (1.1)² + (11 - 1) × (1.7)²] / (10 + 11 - 2)} × (1/10 + 1/11))
= √( { [(9) × 1.21 + (10) × 2.89] / (19) } × (0.1909))
= √({[ 39.79 ] / 19} × (0.1909))
= √( 2.0942 × 0.1909)
= √( 0.39978 )
= 0.63228
Now Test Statistics will be;
t = ( x"₁ - x"₂) / sp
we substitute
t = ( 6.4 - 5.6) / 0.63228
t = 0.8 / 0.63228
t = 1.2653
Therefore the value for the associated test statistic is 1.2653
Answer: 28 hours
Step-by-step explanation:
Hi, the cost for the trampoline park without a membership is equal to the price of the jump tickets per hour (12) multiplied by the number of hours (h).
Cost without membership= 12h
With the membership the price of each jump ticket has a 15% discount ( so, 100-15 =85% of the total price ). To calculate the cost for this case we have to add the cost of the membership 50, and multiply the cost of each jump ticket (12) by 0.85 (percentage in decimal form)
Cost with membership = 50 +12 (0.85) h
If both cost are equal:
50 +12 (0.85) h = 12 h
Solving for h
50+10.2h =12h
50= 12h-10.2h
50= 1.8h
50/1.8= h
27.78 =h
h =28 (rounded)
Use slope formula to find slope
<span><span><span>−9−5</span><span>−/12−8</span></span>=<span><span>−14/</span><span>−20</span></span>=<span>7/10</span></span>
7/10 = m = slope
y= mx + b
y= (7/10)x + b
(8,5)
(5) = (7/10)(8) + b
b = -3/5
So....
<span>y=(<span>7/10)</span>x −<span>35
</span></span>
multiply by 10
<span>10y=7x−6</span><span>
--> -7x + 10y = -6
--> 7x - 10y = 6
So, if 7x - 10y = 3 a good model?</span>
Answer:H
Step-by-step explanation:
Answer:
$ 1850
Step-by-step explanation:
As it is simple interest, the interest will be same each year.
Interest = 2312.50 - 2081.25 = $ 231.25
The amount borrowed = 2081.25 - 231.25 = $ 1850
