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1 year ago

Given the domain {-2, 1, 5}, what is the range for the relation 4x + y = 3?

Mathematics

1 answer:

steposvetlana [31]1 year ago

6 0

Answer:

Step-by-step explanation:

Domain is the set of all possible inputs (x) for the function f(x)

The range is the set of all possible values for that domain

This function is 4x + y = 3 which can be re-written as y = 3-4x

Plug in each of the domain values and you will get the range

For -2 : y = 3-4(-2) = 3 + 8 = 11

For 1: y = 3-4(1) = -1

For 5: y = 3-4(5) = -17

So range is {-17, -1, 11}

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3 years ago

What’s the answer for this question

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Answer:

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Step-by-step explanation:

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3 years ago

Alex swims 20 minutes per day for exercise. The total

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Answer:

e total number of minutes, m.

Step-by-step explanation:

The dependent variable is the variable in which the variable cannot stand by itself.

In this situation, the total number of minutes, m, equal 20 times the number of d.

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Step-by-step explanation:

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3 years ago

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Sladkaya [172]

Answer:

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Step-by-step explanation:

5 × 3

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2 years ago

Read 2 more answers

Find all the values of x in the set of complex numbers that satisfy the following equation:

Fynjy0 [20]

Compute all the component integrals first:

$I_1=\displaystyle\int_0^{\pi/4}2\sec x\,\mathrm dx=2\ln(\sqrt2+1)$
$I_2=\displaystyle\int_0^2\ln x\,\mathrm dx=2(\ln2-1)$
$I_3=\displaystyle\lim_{a\to\infty}\int_{-a}^a\frac{\mathrm dx}{x^2+1}=\pi$

Now,

$\sqrt2\approx1.4\implies \sqrt2+1\approx2.4$
$\implies \left\lceil I_1\right\rceil=2$

$e$
$\implies\left\lfloor I_2\right\rfloor=-1$

$\pi\approx3.14\implies\left\lceil I_3\right\rceil=4$

So the given equation reduces to

$\displaystyle\sum_{k=-1}^2\frac{\mathrm d}{\mathrm dx}x^{k+2}=1-4!$
$\dfrac{\mathrm dx}{\mathrm dx}+\dfrac{\mathrm dx^2}{\mathrm dx}+\dfrac{\mathrm dx^3}{\mathrm dx}+\dfrac{\mathrm dx^4}{\mathrm dx}=-23$
$4x^3+3x^2+2x+24=0$

a fairly standard cubic. Incidentally, when $x=-2$ , the LHS reduces to 0, so $x+2$ is a factor of the cubic. You can find the remaining two solutions easily with the quadratic formula.

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3 years ago