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RideAnS [48]
2 years ago
8

Having trouble question is in attachment

Mathematics
1 answer:
Sunny_sXe [5.5K]2 years ago
3 0

Answer:

x=\frac{35}{9} .

Step-by-step explanation:

(3\sqrt{3})^{-x+1} =\frac{1}{3}*27^{x-5}\\( \sqrt{3^2*3}) ^{1-x}=\frac{1}{3} *((3)^3)^{x-5}\\(\sqrt{27} )^{1-x}=\frac{1}{3}*3^{3*(x-5)}\\ (\sqrt{3^3})^{1-x} =\frac{1}{3}*3^{3x-15}\\ 3^{\frac{3 }{2}*(1-x)}=\frac{1}{3}*3^{3x-15}\ |*3\\ 3*3^{\frac{3}{2}-\frac{3}{2}x}=3^{3x-15}\\ 3^{1+1,5-1,5}=3^{3x-15}\\ 3^{2,5-1,5x}=3^{3x-15}\ \ \ \  \Rightarrow\\2,5-1,5x=3x-15\\4,5x =17,5\ |*2\\9x=35\ |:9\\x=\frac{35}{9}.

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3 years ago
(Adding and Subtracting Polynomials)
andrey2020 [161]

Adding and subtracting big polynomials like these are pretty easy. You just need to combine like terms. For example:

1.)

{5x}^{2}  +  {3x}^{2}  =  {8x}^{2}

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({3x}^{2}  + 5xy) + (7xy + 2) =

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All you have to do is combine the numbers that have the same powers of x and y with each other. x^2 will combine with x^2 and xy^2 wil combine with xy^2 exc. If there is no other number with the same x and y's, then you just leave it as it is in the answer.

Now with the original question, I see a -9xy^3, and thats gonna combine with the 3xy^3 in the second polynomial and the 2xy^3 in the third one.

- 9x {y}^{3}  + 3x {y}^{3}  + 2x {y}^{3} = \\  - 4x {y}^{3}

So far we have -4xy^3, the next term is going to be a -9x^4y^3, and that's gonna combine with the 3x^4y^3 in the third one.

- 9 {x}^{4} {y}^{3}  + 3 {x}^{4}  {y}^{3}  =  - 6{x}^{4}  {y}^{3}

We now finished adding the like terms that were in the first polynomial, we will move onto the second polynomial. The first term in this one is 3xy^3, in which we already added in the first step. At this point, it doesn't look like there are any other terms that have the same x and y behind them. So we can move on and write the final answer:

- 4x {y}^{3} - 6 {x}^{4} {y}^{3}  + 7 {y}^{4}  \\ - 8 {x}^{4} {y}^{4}

(All on the same line of course)

Also, for your second question, the order does not matter in which you write the terms. I could write the 7y^4 behind the -8x^4y^4 and it would still be the same answer.

If you have any other questions let me know :) while I double check my work.

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