Question

Mr. shaw graphs the function f(x) = –5x 2 for his class. the line contains the point (-2, 12). what is the point-slope form of the equation of the line he graphed? y – 12 = –5(x 2) y – 12 = 2(x 2) y 12 = 2(x – 2) y 12 = –5(x – 2)

Answer 1

y - 12 = -5(x + 12) is the required equation.

f(x) = -5x + 2

let f(x) = y

y = -5x + 2

y = -5x + 2

comparing it to y = mx + c

m = -5

The point slope form is used to find the equation of the straight line which is inclined at a given angle to the x-axis and passes through a given point. The equation of a line is an equation that is satisfied by each and every point on the line. This means that a linear equation in two variables represents a line.

The point slope equation formula is

y - y₁ = m(x - x₁)

Now the equation of line containing (-2,12) is

$y - {y}_1= m(x - {x}_1)$

y - 12 = -5(x + 12)

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