Given the functions
(a) f(x) = x³ + 5x² + x
(b) f(x) = x² + x
(c) f(x) = -x
Function (a)
f(-x) = (-x)³ + 5(-x)² + (-x)
= -x³ + 5x² - x
= -(x³ - 5x² + x)
The function is neither even nor odd.
Function (b)
f(-x) = (-x)² + (-x)
= -(-x² + x)
The function is neither even nor odd.
Function (c)
f(-x) = -(-x)
= x
= -f(x)
Because f(-x) = -f(x) the function is odd.
Answer: f(x) = -x is an odd function.
√(x-5) = √(3-x)
|x-5| = |3-x|
x-5= 3-x
2x = 8
x=4
Let the smaller one is x so the larger is x+1
x(x+1)=1332
x^2+x=1332
x^2 +x -1332 =0
(x - 36)(x + 37) =0
so x = 36 or x = -37
therefor the larger integer is either 37 or -36
90.42857143 or
90.4 to nearest decimal
Hi there!
To solve, we can use right triangle trigonometry.
Recall that:
sin = O/H, cos = A/H, tan = O/A.
For angle G, HF is its OPPOSITE side, and FG is the hypotenuse.
Therefore, we must use sine to evaluate:
sinG = 14 / 17
sin⁻¹ (14/17) = ∠G. Evaluate using a calculator.
∠G ≈ 55.44°
