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Tresset [83]
2 years ago
7

ILL MARK BRAINLIST IF ITS RIGHT.

Mathematics
1 answer:
erastovalidia [21]2 years ago
3 0

Answer:

Step-by-step explanation:

The formula you should use is

b = 7 * h

You can try any value to see what happens

Let h = 3

b = 3*7

b = 21

4

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PLZZZZZ NEED HELP!!!!!!
mylen [45]

Remember the rules of Sohcahtoa (Sine, cosine, tangent). For this problem we take the cosine of 38 because the labeled sides are the adjacent leg and the hypotenuse.

Cos(38)=79/x

Cosine of 38 is about 0.7880

0.7880=79/x

Next we multiply both sides by the denominator

(x) 0.7880=79 (x)

Then divide.

<u>0.7880x</u>= <u>79</u>

0.7880 0.7880

X=100.25

Hope this helped :)

5 0
3 years ago
En una reunión de 40 viejos piratas, 1/5 tenían una pata de palo y los 3/4 de ellos habían navegado en El Corsario. ¿Cuántos pir
Serga [27]

Answer:

spanish

Step-by-step explanation:

4 0
3 years ago
-7-(-7)=? Plz help plz plz
Reil [10]

Answer:

the answer is 0

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Solve the equation : |x| - 6 = 4
wlad13 [49]

Answer:

x=10

Step-by-step explanation:

10-6 is equal to 4. The absolute value of 10 is 10. Therefore, x=10. Brainliest?

6 0
3 years ago
I have the question in a screengrab. Thank you, whoever helps me.
nata0808 [166]

To simplify

\sqrt[4]{\dfrac{24x^6y}{128x^4y^5}}

we need to use the fact that

\sqrt[4]{x^4}=|x|

Why the absolute value? It's because (-x)^4=(-1)^4x^4=x^4.

We start by rewriting as

\sqrt[4]{\dfrac{2^23x^6y}{2^6x^4y^5}}

\sqrt[4]{\dfrac{2^23x^4x^2y}{2^42^2x^4y^4y}}

Since x\neq0, we have \dfrac xx=1, and the above reduces to

\sqrt[4]{\dfrac{3x^2y}{2^4y^4y}}

Then we pull out any 4th powers under the radical, and simplify everything we can:

\dfrac1{\sqrt[4]{2^4y^4}}\sqrt[4]{\dfrac{3x^2y}{y}}

\dfrac1{|2y|}\sqrt[4]{3x^2}

where y>0 allows us to write \dfrac yy=1, and this also means that |y|=y. So we end up with

\dfrac{\sqrt[4]{3x^2}}{2y}

making the last option the correct answer.

7 0
3 years ago
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