You could calculate the area of the trapezoid and then subtract the area of the triangle.
Area of a trapezoid:
Plug values in:
Add 6 and 12:
Simplify:
Area of a triangle:
Plug values in:
Simplify:
A = 36
Subtract the area of the triangle from the area of the trapezoid
54 - 36 = 18
You could also calculate the area of the shaded region by assuming that they're congruent meaning the base would be half of 6 which is 3 and the height would be 6 so the area of one would be 1/2 (6)(3) but since they're is 2 you wouldn't need the 1/2 since multiplying by 2 would cancel it out so the area would be (6)(3) = 18
When the lines are parallel then there is no solution to the system of equations. This happens because the intersection is the solution. And when there is no intersection then there is no solution.