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kogti [31]
1 year ago
5

Fill in the missing statements and reasons in this proof. Number your reasons 1 through 5 as they would be shown in the chart be

low.
Given: m∠LOM = m∠JKI;

m∠MON = m∠IKH

Prove: m∠LON = m∠HKJ


would rlly appreciate ur help

Mathematics
1 answer:
Paul [167]1 year ago
5 0

From the given condition m ∠LOM = m ∠JKI, m ∠MON = m ∠IKH it is proved that m ∠LON = m ∠HKJ as they are congruent angles.

<h3>What are congruent angles?</h3>

Congruent angles are defined as angles with equal measure. According to the question,

m ∠LOM = m ∠JKI  (given congruent angles)   _____(1)

m ∠MON = m ∠IKH  (given congruent angles)  _______(2)

Add both the side angle  m ∠MON in (1) we get m ∠LOM + m ∠MON = m ∠JKI + m ∠MON

Replace angle  m ∠MON = m ∠IKH from (2)  on right-hand side we get,

m ∠LOM + m ∠MON = m ∠JKI + m ∠IKH  ____(3)

m ∠LOM + m ∠MON = m ∠LON  ( M is the interior point of ∠LON)  ___(4)

m ∠JKI + m ∠IKH = m ∠HKJ  ( I is the interior point of ∠HKJ)  ___(5)

Form (3), (4), and (5) we get, m ∠LON = m ∠HKJ  (Congruent angles)

Hence, from the given condition it is proved that m ∠LON = m ∠HKJ, are congruent angles.

Learn more about congruent angles on:

brainly.com/question/24887947

#SPJ1

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10) what is the area ratio<br> 11) what is the area of RST <br> HELP ASAP EMERGENCY
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9514 1404 393

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  10)  C 4/9

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8 0
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Which classification describes AMNO with vertices M(2, -3), N(3, 1), and<br> 0(-3, 1)?
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Option D

Step-by-step explanation:

32). Given vertices of the triangle are M(2, -3), N(3, 1) and O(-3. 1).

Distance between two points (x_1,y_1) and (x_2,y_2) is given by the expression,

Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance between M(2, -3) and N(3, 1) will be,

MN = \sqrt{(3-2)^2+(1+3)^2}

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Distance between M(2, -3) and O(-3, 1),

MO = \sqrt{(2+3)^2+(-3-1)^2}

      = \sqrt{25+16}

      = \sqrt{41}

Distance between N(3, 1) and O(-3, 1),

NO = \sqrt{(3+3)^2+(1-1)^2}

      = 6

Condition for right triangle,

c² = a² + b² [Here c is the longest side of the triangle]

By this property,

MO² = MN² + NO²

(\sqrt{41})^2=(\sqrt{17})^2+6^2

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False.

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