The solution is x=-3, y=1, z=-1
Answer:
3 ways
Step-by-step explanation:
n = 3; r = 2
Answer:
a) one solution
b) no solution
Step-by-step explanation:
Systems of equations can be described as having one solution, no solution or infinite solutions:
One solution: 'x' and 'y' are equal to only one value
No solution: 'x' and 'y' can not be solved with the given equations
Infinite solutions: values for 'x' and 'y' include all real numbers
In order to evaluate the systems, putting them in the same format is your first step:
a) - y = -5x - 6 or y - 5x = 6
y - 5x = -6
Since both equations have the same expression 'y - 5x', but there are equal to opposite values, this system would have no solution, as this would not be possible to calculate.
b) y + 3x = -1
y = 3x -1 or y - 3x = -1
Solving for 'y' by adding the equations and eliminating 'x', gives us:
2y = -2 or y = -1
Using y = -1 to plug back into an equation and solve for 'x': -1 + 3x = -1 or x = 0. Since 'x' and 'y' can be solved for a value, the system has just one solution.
Answer:
x² + x - 12 = 0
Step-by-step explanation:
Given the solutions are x = - 4 and x = 3, then the factors are
(x + 4) and (x - 3) and the equation is the product of the factors, that is
(x + 4)(x - 3) = 0 ← expand factors using FOIL
x² + x - 12 = 0 ← in standard form
This written as an expression is 7 >= w > -1
Hope this helps!
