All categories

3 years ago

Which property is illustrated by the following statement? If ZXY= FDE, and FDE= CAB, then ZXY=CAB

Mathematics

2 answers:

WINSTONCH [101]3 years ago

8 0

Answer:

your answer would be transitive property

blagie [28]3 years ago

5 0

Answer:

Transitive property of equality

Step-by-step explanation:

By the definition of transitivity, a relation R is said to be transitive if (a, b) ∈ R and (b, c) ∈ R, then (a, c) ∈ R.

If p = q, q = r then p = r.

Here, we have given that if ZXY = FDE and FDE = CAB, then, ZXY = CAB.

Therefore, it shows the transitive property of equality.

You might be interested in

Find quotient 10/6 / 1/ 24

Maru [420]

Answer:

Step-by-step explanation:

Quotient means dividing so we must divide 10/6 by 1/24.

10/6 ÷ 1/24

10/6 * 24/1 = 40 <--- Multiply by the reciprocal in order to divide.

Final Answer: 40

I hope this helps! :)

3 0

2 years ago

Adiciones racinales 1/7+3/7+2/7

Digiron [165]

6/7 is the awnser for this one

7 0

3 years ago

Rotate the triangle 180 degrees around the origin

neonofarm [45]

If you rotate the triangle 180 degrees around the origin I’ll only go half way of that triangle

5 0

3 years ago

Can y’all help me with this

Aleonysh [2.5K]

Answer:

it's the last one *25,000 J

Step-by-step explanation:

3 0

3 years ago

Can someone please explain how to do these?

Pani-rosa [81]

Answer:

First question answer: The limit is 69

Second question answer: The limit is 5

Step-by-step explanation:

For the first limit, plug in $x=8$ in the expression $(9x-3)$ , that's the answer for linear equations and limits.

So we have:

$9x-3\\9(8)-3\\72-3\\69$

The answer is 69

For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value $x=1$ into the simplified expression to get the correct answer. Shown below:

$\frac{x^2+8x-9}{x^2-1}\\\frac{(x+9)(x-1)}{(x-1)(x+1)}\\\frac{x+9}{x+1}$

Now putting 1 in $x$ gives us the limit:

$\frac{x+9}{x+1}\\\frac{1+9}{1+1}=\frac{10}{2}=5$

So the answer is 5

3 0

3 years ago