Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Answer:
6 possible integers
Step-by-step explanation:
Given
A decreasing geometric sequence

Required
Determine the possible integer values of m
Assume the first term of the sequence to be positive integer x;
The next sequence will be 
The next will be; 
The nth term will be 
For each of the successive terms to be less than the previous term;
then
must be a proper fraction;
This implies that:

<em>Where 7 is the denominator</em>
<em>The sets of </em>
<em> is </em>
<em> and their are 6 items in this set</em>
<em>Hence, there are 6 possible integer</em>
Answer: 6x+18
Step-by-step explanation: Because of the Distributive property, you would multiply the 6 by the’x’ and 3, as they are in the parenthesis.
Answer:
-5
Explanation:
Because it’s right