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2 years ago

I NEED HELP !!! Right now!!!

Mathematics

1 answer:

telo118 [61]2 years ago

3 0

Answer:

Step-by-step explanation:

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Choose the correct answers for (a) the total installment price, (b) the carrying charges, and (c) the number of months needed to

yanalaym [24]

A
100+89.50×36
=3,322
b
3,322−2,900
=422
c
2,900÷89.50
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3 years ago

Read 2 more answers

The lifespan of a lion in a particular zoo are normally distributed. The average lion lives 12.5 years the. Standard deviation i

Anika [276]

Answer:

0.1585

Step-by-step explanation:

Solution:-

The lifespan of a lion in a particular zoo is normally distributed with average lion lives:

Mean u = 12.5 years

Standard deviation s = 2.4 years

We are to use the empirical rule ( 68-95-99.7% ) to estimate the probability of a lion living between 5.3 and 10.1.

- The empirical rule ( 68-95-99.7% ) states:

P ( u - s < X < u + s ) = 68%

P ( u - 2s < X < u + 2s ) = 95%

P ( u - 3s < X < u + 3s ) = 99.7%

- The test have the following number of standard deviations (s):

u - s < X < u + s = 12.5 - 2.4 < X < 12.5 + 2.4 = 10.1 < X < 14.9

u - 2s < X < u + 2s = 12.5 - 4.8 < X < 12.5 + 4.8 = 7.7 < X < 17.3

u - 3s < X < u + 3s = 12.5 - 7.2 < X < 12.5 + 7.2 = 5.3 < X < 19.7

Hence,

P ( 10.1 < X < 14.9 ) = 0.68

P ( 7.7 < X < 17.3 ) = 0.95

P ( 5.3 < X < 19.7 ) = 0.997

- We need P ( X < 10.1 ) and P ( X < 5.3 ):

P ( X < 10.1 ) = [ 1 - P ( 10.1 < X < 14.9 ) ] / 2

= [ 1 - 0.68 ] / 2

= 0.16

P ( X < 5.3 ) = [ 1 - P ( 5.3 < X < 19.7 ) ] / 2

= [ 1 - 0.997 ] / 2

= 0.0015

Hence,

P ( 5.3 < X < 10.1 ) = P ( X < 10.1 ) - P ( X < 5.3 )

= 0.16 - 0.0015

= 0.1585

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3 years ago

Algebra 2 help? please ill give brainliest

ZanzabumX [31]

Sorry for the chicken scratch
It says as x approaches negative infinity y approaches negative infinity and as x approaches positive infinity y approaches negative infinity

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3 years ago

Enter the values for the highlighted variables that show how to subtract the rational expressions correctly:

sladkih [1.3K]

The highlighted variables a = 6 , b = 2, c=6 , d =2 , e=6 , f =6 , g =1

<h3>What is an Expression ?</h3>

An expression is a mathematical statement which consists of variables , constants and mathematical operators.

$\rm \dfrac{2}{x^2-36}-\dfrac{1}{x^2+36}\\= \dfrac{2}{(x+6)(x-6)}-\dfrac{1}{x(x+a)}\\=\dfrac{bx}{x(x+6)(x-6)}-\dfrac{x-c}{x(x+6)(x-6)}\\\\=\dfrac{dx-x+e}{x(x+6)(x-6)}\\\\= \dfrac{x+f}{x(x+6)(x-6)}\\\\=\dfrac{g}{x(x-6)}$