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Misha Larkins [42]
3 years ago
11

Which fraction represent the given fraction rewritten with their LCD?

Mathematics
1 answer:
enot [183]3 years ago
7 0
Please, use ( ) around fractional coefficients:

<span>1/3x-9y, 6/5x-15y  should (probably) be written as (1/3) - 9y and (6/5)x - 15 y.

The LCD here is 3(5) = 15.


Mult. </span><span>1/3x-9y and 6/5x-15y by 15, and then divide the result by 15:

</span>15 [ (1/3)x - 9y and (6/5)x - 15 y ]
---------------------------------------------
                     15


This simplifies to:

5x - 135y  and   18x - 225y
------------            --------------
       15                     15

These fractions are equivalent to the original ones, but now the common denominator, 15, is evident.
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3 years ago
X plus 9 divided by 7 equals 3
zavuch27 [327]

Answer- <em>X=12</em>

Step-by-step explanation:

X + 9/7 = 3 is our equation

Then we are going to do the opposite of dividing 7 from 9 which is multiplying  7 from 9. (on both sides)

It will leave us with - X + 9 = 21

Then we will do the opposite of adding 9 to X which is subtracting 9 from X. (also on both sides) ( whenever you do any adding or subtracting or multiplying or dividing on one side you have to do it on the other for the equation to be true)

Now it will leave us with X = 12

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7 0
3 years ago
Factorise: x³ + 32x + 20.​
LenKa [72]

Answer:

cant be factored

Step-by-step explanation:

7 0
3 years ago
I don't know to find the answer to 8. Can someone explain to me?
lapo4ka [179]
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.

A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'

B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)

C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)

D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n

_____
* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.

The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
7 0
3 years ago
.hoi I need a lil help
mihalych1998 [28]

Answer:

10

Step-by-step explanation:

4+5=9 and 1/2+1/2 =1  so 9+1=10

6 0
3 years ago
Read 2 more answers
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