8. A 15.0 gram unknown piece of metal at 99 oC is added to 75 grams of water at 23 oC. The final temperature of the metal and wa

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1 year ago

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ter is 26 oC. What is the specific heat of the unknown metal? (Remember that the specific heat of water is 4.18 J/g* oC.)

1 answer:

Setler79 [48] · Answer 1 · 2023-05-06T23:39:33+03:00

The specific heat of the unknown metal is 0.859 J/g⁰C.

<h3>Specific heat of the unknown metal</h3>

Heat lost by the unknown metal = Heat gained by water

m₁c₁Δθ₁ = m₂c₂Δθ₂

where;

(15)(c₁)(99 - 26) = (75)(4.18)(26 - 23)

1095c₁ = 940.5

c₁ = 940.5/1095

c₁ = 0.859 J/g⁰C

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