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Daniel [21]
3 years ago
12

I will give brainliest

Chemistry
2 answers:
KonstantinChe [14]3 years ago
4 0

Answer:

a martin year is as twice as long

Explanation:

i think

VLD [36.1K]3 years ago
3 0

Answer:

Different because it depends how long the planets take a single orbit around the sun. :) Hope this helps

Explanation:

You might be interested in
Whats the structure and bonding of sodium chloride
anastassius [24]
Sodium Chloride is ordinary table salt

You have a small sodium atom with a positive charge Na+, and a larger chlorine atom with a negative charge, making it a Chloride ion, Cl-.

This ion formation has resulted from Na transferring one of its electrons to Cl. there opposite charges then attract them to each-other.

Because the electrons are transferred rather than shared, we know that the bond is Ionic, rather than covalent.

Most ionic compounds, if not all, are salts that form a crystal lattice structure, due to the opposite charges in the molecule.

Think of it like this

Na+—Cl-
Cl—-Na+
Na+—Cl-

That’s how the molecules attract and stick to each other. That would continue until you ran out of NaCl molecules.
8 0
3 years ago
What is the instantaneous acceleration of the particle at point B?
luda_lava [24]

__0 meters/second^2__

5 0
3 years ago
2. 2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2
Slav-nsk [51]

Answer:

84.4g of AgCl

Explanation:

Based on the reaction:

2AgNO₃ + CaCl₂ → 2AgCl + Ca(NO₃)₂

<em>2 moles of AgNO₃ and 1 mole of CaCl₂ priduce 2 moles of AgCl and 1 mole of Ca(NO₃)₂</em>

<em />

100g of each reactant are:

AgNO₃: 100g × (1mol / 169.87g) = 0.589 moles

CaCl₂: 100g × (1mol / 110.98g) = 0.901 moles

For a complete reaction of 0.901 moles of CaCl₂ are necessaries 0.901×2 = <em>1.802 moles of AgNO₃. </em>As there are just 0.589moles, <em>AgNO₃ is limitng reactant</em>

<em></em>

0.589 moles of AgNO₃ produce:

0.589 moles × ( 2 moles AgCl / 2 moles AgNO₃) =

<em>0.589 moles of AgC</em>l. In mass:

0.589 moles of AgCl × (143.32g / mol) =<em> 84.4g of AgCl</em>

3 0
4 years ago
Can i get some help i dont get it
Ymorist [56]
The answer will be c}
7 0
4 years ago
What mass of YCL3 forms when 10.0 grams of each reactant are combined?
Triss [41]

The mass of YCl_3 that would be formed will be 18.22 grams

<h3>Stoichiometric calculations</h3>

Let us first look at the balanced equation of the reaction:

2Y + 3Cl_2 --- > 2YCl_3

The mole ratio of Y to Cl_2 is 2:3.

Mole of 10.0 grams of Y = 10/88.9 = 0.11 moles

Mole of 10.0 grams  Cl_2 = 10/71 = 0.14 moles

3/2 of 0.11 = 0.165. Thus,  Cl_2 is limiting in availability.

Mole ratio of  Cl_2 and YCl_3 = 3:2

Equivalent mole of YCl_3 = 2/3 x 0.14 = 0.093 moles.

Mass of 0.093 moles YCl_3 =0.093 x 195.26 = 18.22 grams

More on stoichiometric calculations can be found here: brainly.com/question/27287858

#SPJ1

5 0
2 years ago
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