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Margaret [11]
4 years ago
6

iron reacts with sulfur to form iron sulfide. If 60 grams of iron reacts with sulfur to produce 90 grams of iron sulfide how muc

h sulfur has been used in the chemical reaction
Chemistry
2 answers:
alisha [4.7K]4 years ago
8 0

Answer:

34.44 g.

Explanation:

  • The balanced equation for the reaction is:

<em>Fe + S → FeS,</em>

<em></em>

<em>It is clear that 1.0 mol of Fe reacts with 1.0 mol of S to produce 1.0 mol FeS.</em>

<em />

  • We need to calculate the no. of moles of 60 grams of iron and 90 grams of iron sulfide:

no. of moles of Fe = mass/atomic mass = (60.0 g)/(55.845 g/mol) = <em>1.074 mol.</em>

<em>no. of moles of FeS = mass/molar mass</em> = (90.0 g)/(87.91 g/mol) = <em>1.024 mol.</em>

<u><em>∵ Fe reacts with S with (1: 1) molar ratio.</em></u>

∴ The no. of moles of S needed to react with Fe is 1.074 mol.

<em>∴ The no. of grams of S needed = no. of moles x molar mass </em>= (1.074 mol)(32.065 g/mol) = <em>34.44 g.</em>

Nataly_w [17]4 years ago
8 0

Answer:

The answer is:

<u>A. 30 grams</u>

Explanation:

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The temperature in a town started out at 55 degrees. By the end of the day the temperature dropped to -6 degrees.
garik1379 [7]

Answer:

The choice of the answer is fourth option that is -61 degrees.

Therefore the temperature drop is -61°Centigrade.

Explanation:

Given:

The temperature in a town started out at 55 degrees

Start temperature = 55°Centigrade. (Initial temperature)

End of the Day      = -6°Centigrade. (Final temperature)

To Find:

How far did the temperature drop?

Solution:

We will have,

\textrm{Temperature drop}=\textrm{Final temperature}-\textrm{Initial temperature}

Substituting the above values in it we get

\textrm{Temperature drop}=-6-55\\\\\therefore \textrm{Temperature drop}=-61\° centigrade

Therefore the temperature drop is -61°Centigrade.

4 0
3 years ago
At a certain temperature and pressure, one liter of CO2 gas weighs 1.95 g.
AysviL [449]

Answer:

1.332 g.

Explanation:

  • We can use the general law of ideal gas: <em>PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • At the same T and P and constant V (1.0 L), different gases have the same no. of moles (n):

<em>∴ (n) of CO₂ = (n) of C₂H₆</em>

<em></em>

∵ n = mass/molar mass

<em>∴ (mass/molar mass) of CO₂ = (mass/molar mass) of C₂H₆</em>

mass of CO₂ = 1.95 g, molar mass of CO₂ = 44.01 g/mol.

mass of C₂H₆ = ??? g, molar mass of C₂H₆ = 30.07 g/mol.

<em>∴ mass of C₂H₆ = [(mass/molar mass) of CO₂]*(molar mass) of C₂H₆</em> = [(1.95 g / 44.01 g/mol)] * (30.07 g/mol) =<em> 1.332 g.</em>

<em></em>

7 0
4 years ago
Plz help i’m gonna cry i’m in class rn
iragen [17]

Answer:

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Explanation:

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3 years ago
What was the result of collisions between the early Earth and other, smaller protoplanets?
RoseWind [281]

The trajectory of their motion knocked the Earth into a different orbit.

3 0
4 years ago
If the pressure on a gas is decreased by one-half, how large will the volume change be?
Jet001 [13]

Answer:

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Explanation:

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