Answer is Manganese(ii) chloride
To answer this, you need to know the charges for both Mn and Cl
Mn is in the transition metal category and is unique with having 3 levels of charges
manganese - MN
Manganese(ii) - Mn^2+
Manganese(iii) - Mn^3+
Cl is a nonmetal with the standard charge of Cl^-1
Since you have two charges that don't cancel out, they get switched.
So Cl would receive a positive 2. Because it was a positive 2, we can assume that it starts with Manganese(ii). Then we add chloride to the end of it as it ends with Cl.
First convert to moles:
0.5113 g / 17 g/mol = 0.0301 mol
Now create a ratio based on the reaction provided to solve for the unknown:
4 NH3 / -905.4 kJ = 0.0301 mol NH3 / x kJ
x = -6.808 kJ
Answer:
Esters are both inorganic and organic acids .... Regarding the second question, it is believed that it is carried out in this way in order to recognize the C-terminal amino acid in a peptide within a protein
Explanation:
The explanation of this question is according to what was interpreted in the question, since it is considered that it is poorly written ...
What happens in this chemical reaction is that it first becomes an ester (organic or inorganic acid) so that it is later recognized in the complex peptide structure.
2HgO=2Hg + O2
433,18 g. = 32 g
x. = 250 g
x= 3 384,21875 g of HgO is needed
