<em>The cathode is Y</em>
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Further explanation</em></h3>
Electrolysis uses electrical energy to carry out redox reactions that are not spontaneous.
The ions in the solution flowing electrically will move towards to opposite charge of the electrode
The electrolysis material is an electrolyte which can be a solution or a melt.
In positive pole electrolysis cells - the anode is the site of the oxidation reaction, while the negative pole - the cathode is the reduction reaction site.
The result of the reaction in the anode is based on a substance that easily oxidized while the reaction in the cathode is based on a substance that easily reduced.
Electrons (electricity) enter an electrolysis cell through the negative pole (cathode)
The negative ion from the solution will move towards the positive electrode and release the electrons around the positive electrode (oxidation) and the electrons flow to the negative pole
Whereas around the negative electrode, there is electron binding and a reduction reaction occurs
So if we see the picture the cathode is Y
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Learn more</em></h3><h3><em>
reaction related to electrochemistry brainly.com/question/3461108</em></h3>
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Answer details </em></h3>
Grade: Senior High School
Subject: Chemistry
Chapter: Electrochemistry
Keywords: cathode, anode, oxidation, reduction, negative pole, electrode
Answer:
the answer is False I hope this helps
Hey there!
Find molar mass of C₆H₂Cl₄.
C: 6 x 12.01
H: 2 x 1.008
Cl: 4 x 35.45
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215.876g
This is the mass of 1 mole of C₆H₂Cl₄.
Multiply 215.876 by 5.99.
215.876 x 5.99 = 1293
The mass of 5.99 moles of C₆H₂Cl₄ is 1293 grams.
Hope this helps!
Answer:
V = 14.2 L
Explanation:
Given data:
Moles of CO₂ = 0.632 mol
Temperature = standard = 273 K
Pressure = standard = 1 atm
Volume of gas = ?
Solution;
Formula:
PV = nRT
R = general gas constant = 0.0821 atm.L/ mol.K
Now we will put the values in formula.
V = nRT/P
V = 0.632 mol ×0.0821 atm.L/ mol.K × 273 K / 1 atm
V = 14.2 L/ 1
V = 14.2 L
