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tatiyna
2 years ago
13

A small hole in the wing of a space shuttle requires a 16.2 cm2 patch. (b) If the patching material costs NASA $3.58/in2, what i

s the cost of the patch to the nearest cent?
Chemistry
1 answer:
Tju [1.3M]2 years ago
6 0

The cost of the patch : = 887.84 cents

<h3>Further explanation</h3>

Given

16.2 cm² patch

cost = $3.58/in²

Required

The cost of the patch

Solution

We must pay attention to the conversion factor when changing units

1 cm² = 0.155 in²

16 cm² = 2.48 in²

Cost :

= $3.58/in² x 2.48 in²

= $8.8784

1 dollar is equal to 100 cents, so :

= $8.8784 x 100 cents/$

= 887.84 cents

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To make use of an ionic hydrate for storing solar energy, you place 422.0 kg of sodium sulfate decahydrate on your house roof. A
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Complete Question

To make use of an ionic hydrate for storing solar energy, you place 422.0 kg of sodium sulfate decahydrate on your house roof. Assuming complete reaction and 100% efficiency of heat transfer, how much heat (in kJ) is released to your house at night? Note that sodium sulfate decahydrate will transfer 354 kJ/mol.

Answer:

The amount of energy released is x = 4.63650 *10^5 KJ

Explanation:

Number of moles is mathematically represented as

                         n =\frac{mass}{Molar\ Mass}

substituting 422.0kg = 422 *10^3g for mass of sodium sulfate decahydrate(Na_2 SO_4 \cdot 10H_2 O), 322.2g/mol (This value is a constant )for the molar mass of sodium sulfate decahydrate

                        n= \frac{422*10^3}{322.2}

                           = 1309.7 \ moles

From the question we are told that

            1 mole of sodium sulfate decahydrate generates 354KJ of energy

         So  1309.7 mole would generate  x

Now stating the relation mathematically

                 1 mol → 354KJ

                 1309.7 mol → x

=>      x = 4.63650 *10^5 KJ

                   

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