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Angelina_Jolie [31]
2 years ago
12

A dial combination lock has dials numbered 0 to 5. The lock is set to an even number. How many different numbers could it be?

Mathematics
1 answer:
Butoxors [25]2 years ago
3 0

The number of combinations will be 6 for even numbers.

<h3>What is the combination?</h3>

The arrangement of the different things or numbers in a number of ways is called the combination.

Given that:-

  • A dial combination lock has dials numbered 0 to 5. The lock is set to an even number. How many different numbers could it be?

The total sample numbers are from 0 to 5 which are 0,1,2,3,4,5.

The even numbers are 0,2,4.

The combinations will be given by:-

C = 3!

C = 3 x 2 x1

C = 6

Therefore the number of combinations will be 6 for even numbers.

To know more about Combinations follow

brainly.com/question/295961

#SPJ1

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Last one anyone that can help me out?
Usimov [2.4K]

Answer:

Part a. t = 7.29 years.

Part b. t = 27.73 years.

Part c. p = $3894.00

Step-by-step explanation:

The formula for continuous compounding is: A = p*e^(rt); where A is the amount after compounding, p is the principle, e is the mathematical constant (2.718281), r is the rate of interest, and t is the time in years.

Part a. It is given that p = $2000, r = 2.5%, and A = $2400. In this part, t is unknown. Therefore: 2400 = 2000*e^(2.5t). This implies 1.2 = e^(0.025t). Taking natural logarithm on both sides yields ln(1.2) = ln(e^(0.025t)). A logarithmic property is that the power of the logarithmic expression can be shifted on the left side of the whole expression, thus multiplying it with the expression. Therefore, ln(1.2) = 0.025t*ln(e). Since ln(e) = 1, and making t the subject gives t = ln(1.2)/0.025. This means that t = 7.29 years (rounded to the nearest 2 decimal places)!!!

Part b. It is given that p = $2000, r = 2.5%, and A = $4000. In this part, t is unknown. Therefore: 4000 = 2000*e^(2.5t). This implies 2 = e^(0.025t). Taking natural logarithm on both sides yields ln(2) = ln(e^(0.025t)). A logarithmic property is that the power of the logarithmic expression can be shifted on the left side of the whole expression, thus multiplying it with the expression. Therefore, ln(2) = 0.025t*ln(e). Since ln(e) = 1, and making t the subject gives t = ln(2)/0.025. This means that t = 27.73 years (rounded to the nearest 2 decimal places)!!!

Part c. It is given that A = $5000, r = 2.5%, and t = 10 years. In this part, p is unknown. Therefore 5000 = p*e^(0.025*10). This implies 5000 = p*e^(0.25). Making p the subject gives p = 5000/e^0.25. This means that p = $3894.00(rounded to the nearest 2 decimal places)!!!

4 0
3 years ago
What is the value of 4/7 x 0.3 ÷ 1/6
Alik [6]
1.03 Is approximately your answer
5 0
3 years ago
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What does it mean to say that two variables are positively​ associated?
stealth61 [152]

Answer:

Option A is correct.

Step-by-step explanation:

Correlation coefficients tell us how strongly the two variables are associated.

A positive correlation is a relation when both the variables move together in the same direction. Like if value of first increases the other also increases.

When the correlation coefficient is greater than 0, this means that both variables are correlated.

So, the answer here will be :

A. There is a linear relationship between the​ variables, and whenever the value of one variable​ increases, the value of the other variable increases.

3 0
3 years ago
50 POINTS find the length of ab plz help me
Umnica [9.8K]

Answer:

about 9.4 units

Step-by-step explanation:

Distance formula:

√(x1 - x2)² + (y2 - y1)²

Coordinates:

A (4, 2)

B (9, 10)

Let's make 9 = x1

Let's make 4 = x2

Let's make 10 = y1

Let's make 2 = y2

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√(x1 - x2)² + (y2 - y1)²

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≈ 9.4

Therefore, the length of AB is approximately 9.4 units.

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Answer:

The graph is sketched by considering the integral. The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.    

Step-by-step explanation:

We sketch the integral ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ. We consider the inner integral which ranges from r = 0 to r = 6/cosθ. r = 0 is located at the origin and r = 6/cosθ is located on the line  x = 6 (since x = rcosθ here x= 6)extends radially outward from the origin. The outer integral ranges from θ = 0 to θ = π/4. This is a line from the origin that intersects the line x = 6 ( r = 6/cosθ) at y = 1 when θ = π/2 . The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.    

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