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Angelina_Jolie [31]
2 years ago
12

A dial combination lock has dials numbered 0 to 5. The lock is set to an even number. How many different numbers could it be?

Mathematics
1 answer:
Butoxors [25]2 years ago
3 0

The number of combinations will be 6 for even numbers.

<h3>What is the combination?</h3>

The arrangement of the different things or numbers in a number of ways is called the combination.

Given that:-

  • A dial combination lock has dials numbered 0 to 5. The lock is set to an even number. How many different numbers could it be?

The total sample numbers are from 0 to 5 which are 0,1,2,3,4,5.

The even numbers are 0,2,4.

The combinations will be given by:-

C = 3!

C = 3 x 2 x1

C = 6

Therefore the number of combinations will be 6 for even numbers.

To know more about Combinations follow

brainly.com/question/295961

#SPJ1

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Answer: 1 1/2 yards of yarn

Step-by-step explanation: For this problem, we will simply be multiply 1/2 yard by 3 to get the amount of yard that Ahlam will need.

1/2 x 3/1 = 3/2 or 1 1/2 yards of yarn. Basically you multiply the top of the fractions first (1 x 3) = 3 Then, you multiply the bottom of the fractions second  (2 x 1) = 2    (3/2 or 1 1/2)

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Step-by-step explanation:

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4 years ago
Consider the following system.
amm1812

Answer:

x = 1  y = 3

Step-by-step explanation:

4x - 1 = -3x + 6          Substitute the first equation for y in the second equation

+3x       + 3x              Add 3x to both sides

7x - 1 = 6

    + 1   +1                   Add 1 to both sides

7x = 7                         Divide both sides by 7

x = 1

Now plug this into the first equation

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A computer consulting firm presently has bids out on three projects. Let Ai = {awarded project i}, for i = 1, 2, 3, and suppose
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Step-by-step explanation:

The data below is what was provided in the question and it is what I solved the question with

P(A1) = 0.23

P(A2) = 0.25

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P(A1 n A3) = 0.11

P(A2 n A3) = 0.07

P(A1 n A2 n A3) = 0.02

a

P(A2|A1) = P(A1 n A2)/P(A1)

= 0.09/0.23

= 0.3913

We have 39.13% confidence that event A2 will occur given that event A1 already occured

b.)

P(A3 n A3|A1) = P(A2 n A3)n A1)/P(A1)

= 0.02/0.23

= 0.08695

We have about 8.7% chance of events A2 and A3 occuring given that A1 already occured.

C.

P(A2 u A3|A1)

= P(A1 n A2)u(A1 n A3)/P(A1)

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We have 78.26% chance of A2 or A3 happening given that A1 has already occured.

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Which equation of a line passes through the points (-5,2) and (0,7)?​
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Answer:

I think the answer will be Y=X+7

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