Answer:
1. x = 65
2. x = 40
3. x = -7
4. x = -4
5. x = -7
6. x = 4
Step-by-step explanation:
Angles in a triangle always add up to 180 degrees.
Thus, for each triangle you can write an equation setting the sum of the three angles equal to 180, and solving for x.
1. 180 = 80 + 35 + x
180 - (80 + 35) = x
180 - 115 = x
65 = x
2. 180 = 70 + 70 + x
180 - (70 + 70) = x
180 - 140 = x
40 = x
3. 180 = 76 + 41 + (x+ 70)
180 - (76 + 41) = x + 70
180 - 117 = x + 70
63 = x + 70
63 - 70 = x
-7 = x
4. (the red square means its a right angle = 90 degrees)
180 = 90 + 25 + (x + 69)
180 - (90 + 25) = x + 69
180 - 115 = x + 69
65 = x + 69
65 - 69 = x
x = -4
5. 180 = 50 + (57 +x) + (x + 87)
180 - 50 = (57 +x) + (x + 87)
130 = (57 +x) + (x + 87)
combine like terms
130 = 144 + 2x
130 - 144 = 2x
-14 = 2x
-7 = x
6. 180 = 80 + (9x + 4) + (16x - 4)
180 - 80 = (9x + 4) + (16x - 4)
100 = (9x + 4) + (16x - 4)
combine like terms
100 = 25x + 0
100 = 25x
4 = x
Answer:
Answer:
y > 2x - 1
y ≤ 0.5x + 4
Step-by-step explanation:
solid line: (0,4) (-8,0)
m: (0-4)/(-8-0) = -4/-8 = 0.5
b: 4
y = mx + b y = 0.5x + 4
dotted line: (0,-1) (-2,-5)
m = (-5 - -1)/(-2-0) = 2
b = -1
equation: y = 2x - 1
System: y ≤ 0.5x + 4
y > 2x - 1
Step-by-step explanation:
The answer is 1, I really hope this helped :)
Answer:
a. 
b. 17 years
c. The amount that is currently charged by the college you attend is much higher than the amount charged in two-year college in the present year.
Step-by-step explanation:
a.
Here, x is a the number of years after 2000 and f(x) is the total cost.
To approximate the yearly cost of attending a two-year college in the year 2016, find 
.
b.
To predict in what year the yearly cost of tuition and required fees will exceed $3200, solve 
So,
x is approximately equal to 17 years.
c.
The present year is 2020.
To approximate the yearly cost of attending a two-year college in the present year, find 
The amount that is currently charged by the college you attend is much higher than the amount charged in two-year college in the present year.
The answer to the question
