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Irina18 [472]
3 years ago
6

When the net is folded up, which sides will touch?

Mathematics
1 answer:
timama [110]3 years ago
5 0

Answer:

The correct answer is

D) e and l

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Rationalize the denominator, then simplify 10/sqrt2
kupik [55]

Answer:

5\sqrt{2}

Step-by-step explanation:

To rationalize the denominator, you need to multiply the numerator and denominator by the radical in the denominator (aka. a factor of 1):

\frac{10}{\sqrt{2}}

\frac{10}{\sqrt{2}}*\frac{\sqrt{2}}{\sqrt{2}}

\frac{10\sqrt{2}}{2}

5\sqrt{2}

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3 years ago
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Please help.<br> Is algebra.
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The answer for question 4 is C and the answer for question 5 is D.

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3 years ago
A random sample is selected from a population with mean = 100 and standard deviation = 10. Determine the mean and standard devia
jenyasd209 [6]

The mean and standard deviation of the x sampling distribution for each of the following sample sizes will be N(100,10/\sqrt{41} ), N(100,10/\sqrt{130} ).

<h3>What is the distribution of the sample mean for large samples?</h3>

Suppose X has a distribution with mean \mu and standard deviation \sigma,then,

the distribution of the mean of samples of size n, drawn from the values of X, is normally distributed with a mean equal to the mean of X, and a standard deviation equal to \sigma/\sqrt{n}

Symbolically, we write it as:

X \sim N(\mu, \sigma) \implies \overline{X} \sim N(\mu,\sigma/\sqrt{n} )

A random sample is selected from a population with a mean = of 100 and a standard deviation = of 10.

The mean and standard deviation of the x sampling distribution for each of the following sample sizes.

If N=41

X \sim N(100, 10) \implies \overline{X} \sim N(100,10/\sqrt{41} )

If N=130

X \sim N(100, 10) \implies \overline{X} \sim N(100,10/\sqrt{130} )

Learn more about standard normal distribution here:

brainly.com/question/10984889

#SPJ1

8 0
3 years ago
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aleksandr82 [10.1K]

Answer:

12-27+9Y=5+6=90X5=800

Step-by-step explanation:

6 0
3 years ago
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