Answer: j=0.4
-j+0.8=-0.9j+0.76
-j+0.8+0.9j=-0.9+0.76+0.9j
-0.1j+0.8=0.76
-0.1+0.8-0.8=0.76-0.8
-0.1j=-0.04
-0.1j/-0.1=-0.04/-0.1
j=0.4
Ya have a good day.
Answer:
The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h
Step-by-step explanation:
At noon the location of Lan = 300 km north of Makenna
Lan's direction = South
Lan's speed = 60 km/h
Makenna's direction and speed = West at 75 km/h
The distance Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km
The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km
The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km
Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.
By Pythagoras' theorem, we have;
s² = x² + y²
The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61
ds²/dt = dx²/dt + dy²/dt
2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt
2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900
ds/dt = 900/(2×30·√61) ≈ 1.92
The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h
Answer:
18
Step-by-step explanation:
a^2 + b^2 = c^2
in this case 24 is a and 30 is c
24^2 = 576
30^2 = 900
900 - 576 = 324
the square root of 324 is 18
Answer:
s=-2
Step-by-step explanation:
Answer:
t ≥ 10
Step-by-step explanation:
Since the student needs at least 10 hours of driving time, they need greater than or equal to 10 hours to pass.
