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Zigmanuir [339]
3 years ago
7

For brainiest:):):):):):)

Mathematics
1 answer:
eimsori [14]3 years ago
3 0
#1. Step one) we set find what we can multiply by 5 to get 20, so we divide 20 by 5.
20/5 = 4
Step two) we multiply the bottom denominator (8) by 4
8x4=32
Step three) leave the top numerator the same (20) and replace (d) with 32
Answer : 20/32
#2 step one) we divide 14 by 7
14/7 = 2
Step two) divide 10 by 2
10/2=5
Step three) replace z with 5
Answer) 7/5
#3 step one) divide 24 by 8
24/8=3
Step two) divide 21 by 3
21/3 = 7
Step three) replace (x) for (7)
Answer) 7/8
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a container has 16 1/2 cups of lemonade. Asher gives each of his classmates 3/4 of a cup if lemonade. if asher gives away all of
tankabanditka [31]
Asher would give away 22 cups of lemonade
8 0
3 years ago
Length A is 4 ft. after a dilation is performed length B is 7ft. what was the scale factor used?
kogti [31]
1.75

4 x 1.75 = 7 so that is the answer
5 0
3 years ago
Use Algorithm 7 to schedule the largest number of talks in a lecture hall from a proposed set of talks, if the starting and endi
3241004551 [841]

Answer:

If we arrange the talks from the lowest starting time to the highest ending time we get total of 11 talks.

using algorithm 7 we get answer   (1) - (3) - (6) - (9)   the largest number of talks scheduled.

Step-by-step explanation:

arranging the talks from lowest starting time to the highest ending time.

thus,

  1. 9:00 a.m. and 9:45 a.m.
  2. 9:30 a.m. and 10:00 a.m.
  3. 9:50 a.m. and 10:15 a.m.
  4. 10:00 a.m. and 10:30 a.m.
  5. 10:10 a.m. and 10:25 a.m.
  6. 10:30 a.m. and 10:55 a.m.
  7. 10:15 a.m. and 10:45 a.m.
  8. 10:30 a.m. and 11:00 a.m.
  9. 10:45 a.m. and 11:30 a.m.
  10. 10:55 a.m. and 11:25 a.m.
  11. 11:00 a.m. and 11:15 a.m.

we start from the earliest time as

9:00 a.m. and 9:45 a.m which is (1).

After the talk is finished we pick the nearest time for another talk which starts at

9:50 a.m. and 10:15 a.m which is (3).

After this talk we again pick the nearest time for another talk which becomes

10:30 a.m. and 10:55 a.m which is (6).

and lastly

10:45 a.m. and 11:30 a.m which is (9).

Note: we didn't choose other times because we cannot talk at 2 or 3 places at the same time. so we pick another when one talk is finished.

thus the answer is (1) - (3) - (6) - (9) as the largest number of talks scheduled.

4 0
4 years ago
CAN I GET SOMEONES HELP ASAP!!
PIT_PIT [208]
The answer would be <QRZ

Since you are looking for an angle congruent to <UQR using the alternate interior angles theorem, interior suggests that the angle must be inside the parallel lines, se we can get rid of options <WRT and <TRZ since they are exterior angles

Furthermore, in the alternate interior angles theorem, the two angles must be alternate or opposite of each other which would show that the only possible answer would be <QRZ

hope this helped!


7 0
3 years ago
How many solutions does the equation have?
Irina18 [472]
3(4x-3)-7x=5x-9\\&#10;12x-9-7x=5x-9\\&#10;5x-9=5x-9\\&#10;

It's identity ⇒ B
4 0
4 years ago
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