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DIA [1.3K]
1 year ago
11

Which of the following processes does not facilitate containment?

Chemistry
1 answer:
Marta_Voda [28]1 year ago
7 0

Enrichment of uranium-235 is done. Hence, option A is correct.

<h3>What is the meaning of containment?</h3>

The act, process, or means of keeping something within limits the containment of health costs.

Enrichment is a process of increasing the proportion of fissile isotope found in uranium ore (represented by the symbol 'U') to make it usable as nuclear fuel or the compressed, explosive core of nuclear weapons.

Hence, option A is correct.

Learn more about containment here:

brainly.com/question/3299455

#SPJ1

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If 4.12 l of a 0.850 m-h3po4 solution is be diluted to a volume of 10.00 l, what is the concentration of the resulting solution?
statuscvo [17]

The process in which the concentration of the solution is lessened  by the addition of water is said to be dilution and equation of dilution relates the initial concentration and volume of stock solution with the final concentration and volume of the solution.

Formula is given by:

C_{1}V_{1}=C_{2}V_{2}   (1)

where,

C_{1} is the initial concentration

V_{1} is the initial volume

C_{2} is the final concentration

V_{2} is the final volume

Now,

C_{1} = 0.850 M

V_{1} = 4.12 L

C_{2}  =?

V_{2} = 10.00 L

Substitute the give values in formula (1),

0.850 M\times 4.12L=C_{2}\times 10.00 L

C_{2} =\frac{0.850 M\times 4.12L}{10.00 L}

= 0.3502 M

Thus, the final concentration of theH_{3}PO_{4} solution = 0.3502 M












5 0
2 years ago
A 15.50 gram sample of a gas exerts a pressure of 1.40 atmospheres when held in an 8.00 liter at 22 °C. What is the molar mass (
Lostsunrise [7]

Answer:

33.5 g/mol

Explanation:

PV=nRT

(1.40 atm)(8.00 L)=n(0.08206)(295 K)

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15.50 g/0.463 mol=33.5 g/mol

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What is the Law of Conservation of energy?
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Answer:

<u>~</u><u>Law of Conservation of </u><u>energy~</u>

The law of conservation of energy states that energy can neither be created nor destroyed, only energy can be converted from one form to another.

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Answer:yes

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