Answer:
The answer is aluminum foil.
Electronic configuration of cromium is
Cr-[Ar]4s¹3d⁵
When cromium loses two electrons it becomes Cr⁺².
So its electronic configuration becomes,
Cr⁺²-[Ar]3d⁴
One electron will go from 4s orbital and one electron will go from 3d orbital.
So the answer here is D. [Ar]3d⁴ -because after losing 2 electrons electronic configuration of cromium becomes [Ar] 3d⁴.
From the given observations,
You can see that as the concentration is doubled, half-life is halved.
That is,half-life is inversely proportional to concentration
As t( half-life) ~ 1/a^(n-1)
For this case n = 2,second order reaction.
R = k X a^n
Using the above formula you will get the rate and rate constant.
Answer:
A.)
Explanation:
The first structure accurately represents ethyl ethanoate because there is an ethyl group (2 carbons) directly attached to the oxygen within the parent chain and there are 2 carbons (the eth- in ethanoate) attached to the double bonded oxygen.
The second structure is not ethyl ethanoate. There is an ethyl group directly attached to the oxygen within the parent chain. However, there are 3 carbons attached to the double bonded oxygen. This makes the structure ethyl propanoate.