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dlinn [17]
2 years ago
15

If there are 1.55 x 1024 molecules of hydrogen peroxide (H2O2), what is the mass of thesample? ​

Chemistry
1 answer:
bezimeni [28]2 years ago
8 0

Answer:

87.54 g of H₂O₂

Explanation:

From the question given above, the following data were obtained:

Number of molecules = 1.55×10²⁴ molecules

Mass of H₂O₂ =.?

From Avogadro's hypothesis,

6.02×10²³ molecules = 1 mole of H₂O₂

Next, we shall determine the mass of 1 mole of H₂O₂. This can be obtained as follow:

1 mole of H₂O₂ = (2×1) + (2×16)

= 2 + 32

= 34 g

Thus,

6.02×10²³ molecules = 34 g of H₂O₂

Finally, we shall determine mass of H₂O₂ that contains 1.55×10²⁴ molecules. This can be obtained as follow:

6.02×10²³ molecules = 34 g of H₂O₂

Therefore,

1.55×10²⁴ molecules

= (1.55×10²⁴ × 34)/6.02×10²³

1.55×10²⁴ molecules = 87.54 g of H₂O₂

Thus, 87.54 g of H₂O₂ contains 1.55×10²⁴ molecules.

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<u>Answer:</u>

<em>The energy to turn the ice into water:</em>

  • The energy that is required to change the state of ice into a liquid is obtained in the form of heat energy from the ambient temperature of the warm room.
  • Once this heat energy is absorbed, the individual molecules of ice gain kinetic energy and start vibrating faster.
  • Yet, the temperature of the ice remains constant until the ice reaches its melting point because this energy is first utilised to break all the bonds of the lattice structure of the ice.
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8 0
3 years ago
A gas with a volume of 250 mL at a temperature of 293K is heated to 324K. What is the new volume of the gas?
Natalija [7]

Answer:

The new volume of the gas is 276.45 mL.

Explanation:

Charles's law indicates that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases, and as the temperature decreases, the volume of the gas decreases.

Charles's law is a law that mathematically says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

\frac{V}{T} =k

Analyzing an initial state 1 and a final state 2, it is satisfied:

\frac{V1}{T1} =\frac{V2}{T2}

In this case:

  • V1= 250 mL
  • T1= 293 K
  • V2= ?
  • T2= 324 K

Replacing:

\frac{250 mL}{293 K} =\frac{V2}{324 K}

Solving:

V2=324 K*\frac{250 mL}{293 K}

V2= 276.45 mL

<em><u>The new volume of the gas is 276.45 mL.</u></em>

4 0
3 years ago
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4 0
2 years ago
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6 0
3 years ago
What is the molarity of a solution that has 2.50 moles of NaOH dissolved in 0.500 L of solution?
const2013 [10]

Answer: 5 is the molarity

Explanation:

The molarity formula is moles over liters and that in your case is 2.50 moles divided by .500 L which results in 5 which is your answear hope this helped god bless

5 0
3 years ago
Read 2 more answers
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