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motikmotik
2 years ago
9

New flowers are being planted

Mathematics
1 answer:
Akimi4 [234]2 years ago
7 0

Answer:

45 dandelion × 15 rows= 675

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You have a rack that can hold 30 CDs. You can fit 7 more CDs on the rack before the rack is full. How many CDs are in the rack?
uysha [10]
X = number of cds on the rack

x + 7 = 30
x = 30 - 7
x = 23 <== so there are currently 23 cds on the rack
5 0
3 years ago
Read 2 more answers
How are the coordinates of the extreme value and the equation from part B in the form y=(x-h)^2-c related.
True [87]

The extreme value of y = (x - h)² - c is the vertex of the equation.

<h3>What are extreme values of a function?</h3>

The extreme values of a function are either the maximum or minimum values of the function.

<h3>The equation of a parabola in vertex form</h3>

The equation of a parabola in vertex form with vertex (h', k) is given by

y = a(x - h')² + k and its extreme values are

  • if a > 0  (h', k) is a minimum point and
  • if a < 0 (h', k) is a maximum point.

Since y = (x - h)² - c is the equation of a parabola in vertex form, comparing with y = a(x - h')² + k,

  • h = h'
  • -c = k and
  • a = 1.

So, the cooordinates of the vertex of y = (x - h)² - c is (h, -c).

Now, since a = 1 > 0, (h, -c) is a minimum point.

So, the extreme value of y = (x - h)² - c is the vertex of the equation.

Learn more about extreme value of a function here:

brainly.com/question/13464558

#SPJ1

4 0
2 years ago
I need help quick! <br> what is the coordinate of the midpoint GO
Zolol [24]

0 because the number in the middle is the midpoint.

5 0
3 years ago
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In front of a store, there is a row of parking spaces. Cars park parallel to one another, with the front of each car facing the
Gelneren [198K]

The width used for the car spaces are taken as a multiples of the width of

the compact car spaces.

Correct response:

  • The store owners are incorrect
<h3 /><h3>Methods used to obtain the above response</h3>

Let <em>x</em><em> </em>represent the width of the cars parked compact, and let a·x represent the width of cars parked in full size spaces.

We have;

Initial space occupied = 10·x + 12·(a·x) = x·(10 + 12·a)

New space design = 16·x + 9×(a·x) = x·(16 + 9·a)

When the dimensions of the initial and new arrangement are equal, we have;

10 + 12·a = 16 + 9·a

12·a - 9·a = 16 - 10 = 6

3·a = 6

a = 6 ÷ 3 = 2

a = 2

Whereby the factor <em>a</em> < 2, such that the width of the full size space is less than twice the width of the compact spaces, by testing, we have;

10 + 12·a < 16 + 9·a

Which gives;

x·(10 + 12·a) < x·(16 + 9·a)

Therefore;

The initial total car park space is less than the space required for 16

compact spaces and 9 full size spaces, therefore; the store owners are

incorrect.

Learn more about writing expressions here:

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5 0
2 years ago
2÷9<br><img src="https://tex.z-dn.net/?f=78%20%5Csqrt%7B%7D%20" id="TexFormula1" title="78 \sqrt{} " alt="78 \sqrt{} " align="ab
dimulka [17.4K]

Answer:

2 ÷ 9 ≈ 0.222

√78 ≈ 8.832

3 0
3 years ago
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