Answer:
1) -3/4
2) (6, 0), (0, -4)
3) connect (0,-2) and (8,0) together
Step-by-step explanation:
1) (-2) - (-5) / (-1) - 3 = -3/4
2) x = 0 -3y=12 y = -4, y= 0 2x = 12 x = 6, x intercept = (6, 0) y intercept = (0, -4)
3) x - 4y = 8 this could be written as y = x/4 - 2 and y intercept is (0, -2) and x intercept is (8, 0) so connect these points together and make a line
K=4(5)
k=20
you just plug in 5 for d and multiply normally from there.
<span>It is also called order property of addition. This means that addends can be added in any order and the sum is always the same.</span>
When two balanced dice are rolled, the sum of the dice can be 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, or 12, giving 11 possibilities. th
RUDIKE [14]
False.
There are 36 possible outcomes, corresponding to numbers 1-6 independently appearing on each of the dice. Only one of those outcomes is double-sixes, resulting in a sum of 12. The probability that the sum is 12 is 1/36.
In short, the 11 outcomes listed in your problem statement are not equally-likely.
Answer:
Addition property of equality.
Hope this helps :)