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makkiz [27]
3 years ago
5

When two balanced dice are rolled, the sum of the dice can be 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, or 12, giving 11 possibilities. th

erefore the probability is 1/11 that the sum is 12?
Mathematics
1 answer:
RUDIKE [14]3 years ago
3 0
False.

There are 36 possible outcomes, corresponding to numbers 1-6 independently appearing on each of the dice. Only one of those outcomes is double-sixes, resulting in a sum of 12. The probability that the sum is 12 is 1/36.

In short, the 11 outcomes listed in your problem statement are not equally-likely.
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The length of a rectangle is 4 meters less than three times its width. Its area is 615 square meters. What are the dimensions of
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Area= length*width

width=W

W*(3W-4)=615
3W^2-4W=615
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W=41
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But W cant be a negative number so it is 41m (width)
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tatuchka [14]

Answer:

29

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6 0
3 years ago
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jasenka [17]

Answer:

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Step-by-step explanation:

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7 0
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The given line passes through the points (0, −3) and (2, 3).
Alex Ar [27]
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</span>\bf \begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ 0 &,& -3~) &#10;%  (c,d)&#10;&&(~ 2 &,& 3~)&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope =  m\implies &#10;\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{3-(-3)}{2-0}\implies \cfrac{3+3}{2-0}\implies 3
<span>
so, we're really looking for a line whose slope is 3, and runs through -1, -1

</span>\bf \begin{array}{ccccccccc}&#10;&&x_1&&y_1\\&#10;%  (a,b)&#10;&&(~ -1 &,& -1~)&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope =  m\implies 3&#10;\\\\\\&#10;% point-slope intercept&#10;\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-1)=3[x-(-1)]&#10;\\\\\\&#10;y+1=3(x+1)<span>
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