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Step2247 [10]
1 year ago
11

also can someone check this too? just want to make sure i got the the first part right before proceed further​

Mathematics
2 answers:
Nutka1998 [239]1 year ago
5 0
Yeah it’s right good job lol
Vlada [557]1 year ago
4 0

Answer:

the answers are all right

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kumpel [21]

Answer:

y=x+4

Step-by-step explanation:

8 0
3 years ago
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Segment PH is graphed on the coordinate grid where P is (-31,8) and H is (29,-10). Point E is the midpoint of segment PH. If poi
maks197457 [2]

Answer:

The coordinates of point A are (-11 , 2)

Step-by-step explanation:

- The coordinates of point P are (-31 , 8)

- The coordinates of point H are (29 , -10)

- Point E is the mid-point of segment PH

- The coordinates of the the mid-point are:

→ x=\frac{x_{1}+x_{2}}{2} and y=\frac{y_{1}+y_{2}}{2}

∵ E is the mid-point of segment PH

∴ The x-coordinate of point E is x=\frac{-31+29}{2}=-1

∴ The x-coordinate of point E is -1

∴ The y-coordinate of point E is y=\frac{8+-10}{2}=-1

∴ The y-coordinate of point E is -1

∴ The coordinates of point E are (-1 , -1)

- Point A is graphed \frac{2}{3} of the way along the segment from P to E

- That mean the distances from points P to A is 2 parts and from P to E

  is 3 parts, then the distance from A to E is "3 - 2" = 1 part

- So point A divides the line segment PE at ratio 2 : 1 from P

- The coordinates of the division point are:

→ x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}} and y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}

∵ Point A divides PE at ratio 2 : 1

∵ The coordinates of point P are (-31 , 8)

∵ The coordinates of point E are (-1 , -1)

∴ The x-coordinate of point A is x=\frac{(-31)(1)+(-1)(2)}{2+1}= -11

∴ The x-coordinate of point A is -11

∴ The y-coordinate of point A is x=\frac{(8)(1)+(-1)(2)}{2+1}=2

∴ The y-coordinate of point A is 2

∴ The coordinates of point A are (-11 , 2)

* The coordinates of point A are (-11 , 2)

3 0
3 years ago
2/3+1/2<br> HURRY I NED IT ANSWERED ASAP
Sunny_sXe [5.5K]

Answer:

1 1/6 pls vote branliest

Step-by-step explanation:

8 0
2 years ago
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Hi i just wanna know if i'm right on this math question<br><br> Thank you.
Stolb23 [73]

Answer:

Correct my guy or gal.

Step-by-step explanation:

6 0
3 years ago
Due to a manufacturing error, two cans of regular soda were accidentally filled with diet soda and placed into a 18-pack. Suppos
crimeas [40]

Answer:

a) There is a 1.21% probability that both contain diet soda.

b) There is a 79.21% probability that both contain diet soda.

c)  P(X = 2) is unusual, P(X = 0) is not unusual

d) There is a 19.58% probability that exactly one is diet and exactly one is regular.

Step-by-step explanation:

There are only two possible outcomes. Either the can has diet soda, or it hasn't. So we use the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

A number of sucesses x is considered unusually low if P(X \leq x) \leq 0.05 and unusually high if P(X \geq x) \geq 0.05

In this problem, we have that:

Two cans are randomly chosen, so n = 2

Two out of 18 cans are filled with diet coke, so \pi = \frac{2}{18} = 0.11

a) Determine the probability that both contain diet soda. P(both diet soda)

That is P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{2,2}(0.11)^{2}(0.89)^{0} = 0.0121

There is a 1.21% probability that both contain diet soda.

b)Determine the probability that both contain regular soda. P(both regular)

That is P(X = 0).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{2,0}(0.11)^{0}(0.89)^{2} = 0.7921

There is a 79.21% probability that both contain diet soda.

c) Would this be unusual?

We have that P(X = 2) is unusual, since P(X \geq 2) = P(X = 2) = 0.0121 \leq 0.05

For P(X = 0), it is not unusually high nor unusually low.

d) Determine the probability that exactly one is diet and exactly one is regular. P(one diet and one regular)

That is P(X = 1).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 1) = C_{2,1}(0.11)^{1}(0.89)^{1} = 0.1958

There is a 19.58% probability that exactly one is diet and exactly one is regular.

8 0
3 years ago
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