Answer:
Explanation:
Conversion problems could be solved using dimensional analysis for convenient use and understanding. Dimensional analysis is a technique of multiplying the measure we have by a fraction corresponding to some two equal measures in different units.
In order to apply dimensional analysis here, we firstly need to know that a prefix 'n' stands for 'nano', and nano means 
. In this case, we have nanoliters. Using the prefix, we can find a relationship between nanoliter and liter:
We may now apply dimensional analysis. Since we wish to convert into liters, we'll be multiplying the number we have in nL by a fraction that contains this relationship with liters in the numerator and nanoliters in the denominator, so that nL terms cancel out and we would obtain the final answer in liters:
The mass of the N₂O in the given question is 92.4g.
<h3>What is the moles of N2O in the given conditions?</h3>
STEP1- Apply the ideal gas equation
PV=nRT
STEP2- Put the given values in the equation
P=130kPa, T=298K, V=40L R=8.31
STEP3- Solve the equation
N=PV/RT,
N=130×40/8.31×298
N=2.1moles
N=mass/molecular mass
mass=2.1×44
mass = 92.4g
Hence, the mass of N₂O is 92.4g.
learn more about ideal gas.
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You must use 2.50 mL of the concentrated solution to make 10.0 mL of the dilute solution.
We can use the dilution formula
<em>V</em>_1<em>C</em>_1 = <em>V</em>_2<em>C</em>_2
where
<em>V</em> represents the volumes and
<em>C</em> represents the concentrations
We can rearrange the formula to get
<em>V</em>_2 = <em>V</em>_1 × (<em>C</em>_1/<em>C</em>_2)
<em>V</em>_1 = 10.0 mL; <em>C</em>_1 = 5.00 g/100. mL
<em>V</em>_2 = ?; ____<em>C</em>_2 = 20.0 g/100. mL
∴ <em>V</em>_2 = 10.0 mL × [(5.00 g/100. mL)/(20.0 g/100. mL)] = 10.0 mL × 0.250
= 2.50 mL
The characteristic that is not descriptive of C, would be D. It forms bonds with only itself. It forms bonds with almost all other nonmetals, present, like H,O,N, etc.
It is a salt and salt salt and
