Which three elements affect air pressure?

Electricity and Magnetism are related as electricity can actually make magnetic material (iron, nickel or silver) magnetic. This is called an electro magnet (a temporary magnet created by wrapping coils around a magnetic core (the electricity powers the coils, magnetising the material)).

3 0

3 years ago

Combustion of 25.0 g of a hydrocarbon produces 86.5 g of co2. what is the empirical formula of the compound?

Step2247 [10]

Combustion is a reaction between a combustible substance and oxygen, to ultimately produce carbon dioxide and water. Reaction between carbon and oxygen would give,

C + O2 ------> CO2

Here, we have 86.5 grams of carbon dioxide, CO2, which is a product of combustion. Dividing this mass by the molar mass of CO2, which is 44 grams, we can determine the number of moles of CO2.

 86.5 g CO = 1.966 moles CO2
44 g CO2/ mole

Considering that CO2 is composed of 1 mole of carbon and 2 moles of oxygen, and that with complete combustion, 1 mole of carbon reacts to produces 1 mole of CO2, we can then determine the mass of the carbon in the hydrocarbon fuel.

1.966 moles CO2 x 1 mole C x 12 g C = 23.59 g C
1 mole CO2 1 mole C

We were given 25.0 grams of the fuel hydrocarbon. A hydrocarbon is a substance consisting of carbon and hydrogen. To determine the mass of the hydrogen in the fuel, we simply subtract 23.59 grams from 25.0 grams.

25.0 g - 23.59 g = 1.41 grams Hydrogen

To know the number of moles of hydrogen, we divide the mass of the hydrogen in the fuel by the molar mass of hydrogen, which is 1.01 g/mole. Thus, we have 1.396 mole hydrogen.

To determine the empirical formula, we divide the number of moles carbon by the number of moles hydrogen, and find a factor that would give whole number ratios for the carbon and hydrogen in the fuel,

Carbon: 1.966 mol = 1.408 x 5 (factor) = 7
1.396 mol

Hydrogen: 1.396 mol = 1.00 x 5 (factor) = 5
1.396 mol

Thus, the empirical formula is C7H5

4 0

4 years ago

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