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Zanzabum
4 years ago
15

A sample of a substance that has a density of 0.824 g/mL has a mass of 0.451g. Calculate the volume of the sample.

Chemistry
1 answer:
Allushta [10]4 years ago
8 0
Density can be calculated using the following rule:
density=mass/volume
therefore,
volume=mass/density

we have mass=0.451g and density=0.824g/ml
substituting in the above equation, we can calculate the volume as follows:
volume = 0.451/0.824 = 0.547 ml
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Why do oceanographers take measurements of the conductivity of the
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2 years ago
the concentration of the radio active isotope potassium-40 in a rock sample is found to be 6.25%. what is the age of the rock
julsineya [31]

Answer:

5.0 x 10⁹ years.

Explanation:

  • It is known that the decay of a radioactive isotope isotope obeys first order kinetics.
  • Half-life time is the time needed for the reactants to be in its half concentration.
  • If reactant has initial concentration [A₀], after half-life time its concentration will be ([A₀]/2).
  • Also, it is clear that in first order decay the half-life time is independent of the initial concentration.
  • The half-life of K-40 = 1.251 × 10⁹ years.

  • For, first order reactions:

<em>k = ln(2)/(t1/2) = 0.693/(t1/2).</em>

Where, k is the rate constant of the reaction.

t1/2 is the half-life of the reaction.

∴ k =0.693/(t1/2) = 0.693/(1.251 × 10⁹ years) = 5.54 x 10⁻¹⁰ year⁻¹.

  • Also, we have the integral law of first order reaction:

<em>kt = ln([A₀]/[A]),</em>

where, k is the rate constant of the reaction (k = 5.54 x 10⁻¹⁰ year⁻¹).

t is the time of the reaction (t = ??? year).

[A₀] is the initial concentration of (K-40) ([A₀] = 100%).

[A] is the remaining concentration of (K-40) ([A] = 6.25%).

∴ (5.54 x 10⁻¹⁰ year⁻¹)(t) = ln((100%)/( 6.25%))

∴ (5.54 x 10⁻¹⁰ year⁻¹)(t) = 2.77.

∴ t = 2.77/(5.54 x 10⁻¹⁰ year⁻¹) = 5.0 x 10⁹ years.

8 0
3 years ago
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You deposit $1000 into a savings plan at the end of each
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Answer:

FV = $3506.112

Interest = $506.112

Explanation:

We are given;

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The value of the annuity after 3 years will be gotten from the formula;

FV = A[((1 + i)ⁿ - 1)/i](1 + i)

FV = 1000(((1 + 0.08)³ - 1)/0.08)(1 + 0.08)

FV = 1000(1.08⁴ - 1.08)/0.08

FV = $3506.112

Since you deposited $1000 each year, then after 3 years, total deposited = 3 × 1000 = $3000

Since FV = $3506.112, then interest = $3506.112 - $3000

Interest = $506.112

4 0
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