The path of a ball is modelled by the quadratic function ℎ(t) = −5(t − 2)^2 + 23 where

Mathematics

2 answers:

Maru [420]1 year ago

8 0

Answer:

Step-by-step explanation:

the answer is the y intercept of the equation

sukhopar [10]1 year ago

7 0

Answer:

23m, at t=2s

Step-by-step explanation:

Putting the physics part aside, you can rewrite the height function as

$h(t)= 23 - 5(t-2)^2$ . Now you have a fixed value, 23, and you're subtracting to it a quantity that, being a square, is at least zero. The maximum value of that sum you have when you're not subtracting anything, that is 23. That happens when $5(t-2)^2 = 0 \rightarrow t=2$

Alternatively, if you know how to determine the velocity from that kind of motion, you can find out the speed, and the highest altitude you reach when the speed is zero, which leads to a bunch of calculation for the same result.

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line AB passes through points A(-6,6) and B(12,3) if the equation of the line is written in slope intercept form

Paul [167]

Y=(-1/6)x+5
m=(y2-y1)/(x2-x1)
m=(3-6)/(12-(-6))
m=(-3)/(18)
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y=(-1/6)x+b
6=(-1/6)(-6)+b
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