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Maslowich
3 years ago
5

What is the quadratic in vertex form that has an a value of 8 and a vertex of (5, 6)?

Mathematics
2 answers:
faltersainse [42]3 years ago
8 0

Answer:

y= 8(x-5)² + 6

Step-by-step explanation:

Parabolas have two equation forms, namely; the standard and vertex form.

In the vertex form, y = a(x - h)² + k, the variables h and k are the coordinates of the parabola's vertex.

In this case; a=8, h =5, and k=6

Therefore;

The vertex equation will be

y= 8(x-5)² + 6

Anuta_ua [19.1K]3 years ago
5 0

Answer:

Choice C is correct.

Step-by-step explanation:

We have to find the equation of quadratic equation in vertex form.

We have given a= 8 and vertex =(5,6)

The general form of vertex form of equation is :

y = a(x-c)²+d

Where (c,d)   is the vertex of equation.

Putting the values on above equation we get,

y = 8 (x-5)² +6

y = 8 (x-5)² +6 is the quadratic equation in vertex form.

So, choice C is  correct.

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shtirl [24]

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1360

Step-by-step explanation:

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Determine if AB¯¯¯¯¯¯¯¯ and CD¯¯¯¯¯¯¯¯ are parallel, perpendicular, or neither. Given: A (−1, 3), B (0, 5), C (2, 1), D (6, −1)
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