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Maslowich
3 years ago
5

What is the quadratic in vertex form that has an a value of 8 and a vertex of (5, 6)?

Mathematics
2 answers:
faltersainse [42]3 years ago
8 0

Answer:

y= 8(x-5)² + 6

Step-by-step explanation:

Parabolas have two equation forms, namely; the standard and vertex form.

In the vertex form, y = a(x - h)² + k, the variables h and k are the coordinates of the parabola's vertex.

In this case; a=8, h =5, and k=6

Therefore;

The vertex equation will be

y= 8(x-5)² + 6

Anuta_ua [19.1K]3 years ago
5 0

Answer:

Choice C is correct.

Step-by-step explanation:

We have to find the equation of quadratic equation in vertex form.

We have given a= 8 and vertex =(5,6)

The general form of vertex form of equation is :

y = a(x-c)²+d

Where (c,d)   is the vertex of equation.

Putting the values on above equation we get,

y = 8 (x-5)² +6

y = 8 (x-5)² +6 is the quadratic equation in vertex form.

So, choice C is  correct.

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How many solutions does this linear system have? y = y equals StartFraction 2 over 3 EndFraction x plus 2.x+ 2 6x – 4y = –10
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Answer:

The system has one solution

Step-by-step explanation:

we have the system of equations

y=\frac{2}{3}x+2 ----> equation A

6x-4y=-10 ----> equation B

Solve the system by substitution

substitute equation A in equation B

6x-4(\frac{2}{3}x+2)=-10

6x-\frac{8}{3}x-8=-10

Solve for x

Multiply by 3 both sides to remove the fraction

18x-8x-24=-30

Combine like terms

10x=-30+24

10x=-6

x=-\frac{6}{10}

Simplify

x=-\frac{3}{5}

<em>Find the value of y</em>

y=\frac{2}{3}(-\frac{3}{5})+2

y=-\frac{6}{15}+2

y=\frac{24}{15}

Simplify

y=\frac{8}{5}

The solution of the system is the point (-\frac{3}{5},\frac{8}{5})

therefore

The system has one solution

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Step-by-step explanation:

There are two distinct statements but put together, it is:

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