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Irina-Kira [14]
2 years ago
6

Suzanne is looking at taking out a personal loan. Opportunity Loans is offering her $1600 at 3.45% for 1 year, with interest com

pounding monthly. General Loans is offering her $1600 at 4.2% for 1 year, with interest compounding quarterly. Assuming she makes no payments until the 1 year is up, how much interest will have accrued on each loan? On which loan will she earn the least amount of interest?
Mathematics
1 answer:
AleksAgata [21]2 years ago
8 0

Step-by-step explanation:

So the general formula for compound interest is A = P(1+\frac{r}{n})^{nt} where r is the interest rate, t is the time in years, and n is the amount of compounds per year. So plugging in the values for both equations you'll get

Opportunity Loans:

 A = 1600(1+\frac{0.0345}{12})^{(12)(1)}

 A = 1600(1.002875)^{12}

 A \approx 1600(1.035)

 A = \$1,656.08

  Now to find the interest accrued on this loan you simply subtract 1600 from the A or final amount

 Interest=1656.08-1600\\Interest=56.08

General Loans:

 A = 1600(1+\frac{0.042}{4})^{(4)(1)}

 A = 1600(1.0105)^4

 A \approx 1600(1.042)

 A = 1,668.27

 To find the interest we do the same thing we did in the previous problem

 interest = 1668.27-1600\\interest=68.27

Opportunity loans has the least amount of interest after a year

 

 

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Answer:

The answer is -

Number bond: 1 times 56 = 56.

Number bond: 4 times 14 = 56.

Number bond: 7 times 8 = 56.

Step-by-step explanation:

We can define a factor pair as a set of two factors, which, when multiplied together, give a particular product.

For example -

5 and 6 are factors of 30 because 5×6 = 30

Now,

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Number bond: 1 times 56 = 56.                         ...................(1)

Number bond: 4 times 14 = 56.                         ...................(2)

Number bond: 5 times 6 = 56.                         ...................(3)

Number bond: 7 times 8 = 56.                         ...................(4)

In equation (1)

1 times 56 = 1×56 = 56

⇒1 and 56 are the factor pairs of 56

Satisfies

In equation (2)

4 times 14 = 4×14 = 56

⇒4 and 14 are factor pairs of 56

Satisfies

In equation (3)

5 times 6 = 5×6 = 30 ≠ 56

⇒5 and 6 are not factor pairs of 56

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In equation (4)

7 times 8 = 7×8 = 56

⇒7 and 8 are factor pairs of 56

Satisfies

∴ we get

The answer is -

Number bond: 1 times 56 = 56.

Number bond: 4 times 14 = 56.

Number bond: 7 times 8 = 56.

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