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Anna35 [415]
2 years ago
6

Joe has an ice cream stand. last week he spent $85 for ice cream and supplies. he earned $125. what was his profit?

Mathematics
1 answer:
Elodia [21]2 years ago
3 0

Answer:

40 dollars

Step-by-step explanation:

Profit is what he earned minus his costs

Profit = 125 -85

Profit = 40

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Assume that y varies inversely with x. if y = 16 when x = 1/2, find y when x=32​
MissTica

y varies inversely with x.

Example:

If we multiply x by 2 we need to divide y by 2 too.

So,

If y = 16 and x = 1/2, find y when x = 32

Lets see, from 1/2 to 32 e need to multiply 1/2 by 64, right? So let's divide 16 by 64.

16/64 = 8/32 = 4/16 = 2/8 = 1/4

So we can say that:

If y = 16 when x = 1/2, y = 1/4 when x = 32.

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\displaystyle 5,9708213214...\:in.

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Answer:

The Graph of a Quadratic Function

A quadratic function is a polynomial function of degree 2 which can be written in the general form.

Step-by-step explanation:

Example: Graph: f(x)=−x2−2x+3.

Solution:

Step 1: Determine the y-intercept. To do this, set x=0 and find f(0).

f(x)f(0)===−x2−2x+3−(0)2−2(0)+33

The y-intercept is (0,3).

Step 2: Determine the x-intercepts if any. To do this, set f(x)=0 and solve for x.

f(x)000x+3x======−x2−2x+3−x2−2x+3x2+2x−3(x+3)(x−1)0−3orx−1x==Set f(x)=0.Multiply both sides by −1.Factor.Set each factor equal to zero.01

Here where f(x)=0, we obtain two solutions. Hence, there are two x-intercepts, (−3,0) and (1,0).

Step 3: Determine the vertex. One way to do this is to first use x=−b2a to find the x-value of the vertex and then substitute this value in the function to find the corresponding y-value. In this example, a=−1 and b=−2.

x====−b2a−(−2)2(−1)2−2−1

Substitute −1 into the original function to find the corresponding y-value.

f(x)f(−1)====−x2−2x+3−(−1)2−2(−1)+3−1+2+34

The vertex is (−1,4).

Step 4: Determine extra points so that we have at least five points to plot. Ensure a good sampling on either side of the line of symmetry. In this example, one other point will suffice. Choose x=−2 and find the corresponding y-value.

x −2  y 3f(−2)=−(−2)2−2(−2)+3=−4+4+3=3Point(−2,3)

Our fifth point is (−2,3).

Step 5: Plot the points and sketch the graph. To recap, the points that we have found are

y−intercept:x−intercepts:Vertex:Extra point:(0,3)(−3,0) and (1,0)(−1,4)(−2,3)

Answer:

4 0
3 years ago
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