Students in Mr. Jacob's class used a number
1 answer:
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The complex solutions come in pairs and the only difference between them is the sign between the real and imaginary part, so one of the other two solutions is 
. The third solution can be easily found using the rational root theorem, and it's equal to -1.
Answer:
B. More than one quadrilateral exists with the given conditions, and all instances must be isosceles trapezoids.
Step-by-step explanation:
In a parallelogram, adjacent angles are supplementary. They are only congruent if the parallelogram is a rectangle. In this problem, adjacent angles are both congruent and acute. If this were a triangle, it would guarantee the triangle is isosceles.
The fact that opposite angles are supplementary guarantees that the fourth side of the figure is parallel to the base between the acute angles. That makes the figure an isosceles trapezoid. Unless specific angles and side lengths are specified, the description matches <em>any</em> isosceles trapezoid.
