The answer is b or a but I mean it both means the same thing, if this is on Plato it's a
Answer:
b. balance
Explanation:
According to my research on studies conducted by various nutritionists, I can say that based on the information provided within the question this principle of diet planning is called balance. This is the process of choosing different ingredients or foods that give you all the necessary essentials needed to maintain a balanced health and body weight.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Answer:
The ABC overhead for a Deluxe kayak will be $170.93
Explanation:
We are going to divide the overhead cost over the cost driver of each activity.
![\left[\begin{array}{cccc}-&Overhead&Total&Rate\\fabric&246,000&10,000&24.6\\assembly&144,000&32,000&4.5\\setup&110,000&15&7,333.33\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-%26Overhead%26Total%26Rate%5C%5Cfabric%26246%2C000%2610%2C000%2624.6%5C%5Cassembly%26144%2C000%2632%2C000%264.5%5C%5Csetup%26110%2C000%2615%267%2C333.33%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Now we apply the rate to Deluxe Kayak:
![\left[\begin{array}{cccc}-&Rate&Deluxe&Overhead\\fabric&24.6&10,000&246,000\\assembly&4.5&24,000&108,000\\setup&7,333.33&10&73,333.33\\Total&-&-&427,333.33\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-%26Rate%26Deluxe%26Overhead%5C%5Cfabric%2624.6%2610%2C000%26246%2C000%5C%5Cassembly%264.5%2624%2C000%26108%2C000%5C%5Csetup%267%2C333.33%2610%2673%2C333.33%5C%5CTotal%26-%26-%26427%2C333.33%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Finally we divide the overhead for Deluxe between the units produced
427,333.33/ 2,500 = 170.933 = 170.93
Answer:
The answer is D I would say.
Answer:
the correct answer is $150
Explanation:
TC=500 + 150q - 20q^2 + q^3
AVC=(150Q-20Q^2+Q^3)/Q
=150-20Q+Q^2
When AVC is at its minimum means that the marginal cost( CM) is igual to AVC, so we could consider this analysis:
CM= d(TC)/dq =150-40Q+3Q^2
CM=AVC
150-40Q+3Q^2=150-20Q+Q^2
Join similar terms:
150-150-40Q+20Q+3Q^2-Q^2=0
0-20Q+2Q^2=0
Q(-20+2Q)=0
Q_1=0 y Q_2=20/2=10
with q_1 with q_2
150-40*0+3*0=150-20*0+0 150-40*10+3*10^2=150-20*10+10^2
$150=$150 150-400+300 =150-200+100
$50= $ 50
We have two solution if we assume that q=0 like the minimum then the results is $150.
f we assume that q=10 like the minimum then the results is $50.
