Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
D because one thousand nine hundred twenty divided by 8 equals two hundred and forty
Answer:
Find the area of the larger rectangle, then subtract the area of the two smaller rectangles in the corners. Separate the figure into two or three rectangles, and add the areas.
Step-by-step explanation:
this is the sample response
The sum of squares of numbers is: 13
Step-by-step explanation:
Let x and y be two numbers
Then,
Difference of the squares of the numbers will be:
Product will be:
Given identity is:
Given values are:
Difference of the squares of the numbers=
Product of numbers = xy = 6
Putting the values in the identity
![(x^2+y^2)^2=(5)^2+[2(6)]^2\\=25+(12)^2\\=25+144\\=169](https://tex.z-dn.net/?f=%28x%5E2%2By%5E2%29%5E2%3D%285%29%5E2%2B%5B2%286%29%5D%5E2%5C%5C%3D25%2B%2812%29%5E2%5C%5C%3D25%2B144%5C%5C%3D169)
As we have to only find x^2+y^2
Taking square root on both sides
The sum of squares of numbers is: 13
Keywords: Identities
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Answer:
$22.40 im pretty sure its right
Step-by-step explanation:
sorry if im late and mark me brainliest if im right
