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Leviafan [203]
1 year ago
13

Which expression is equivalent to (2x²y) ³? O 2x¹y4 2x¹2y3 8x¹ y O 8x¹2y³

Mathematics
1 answer:
natta225 [31]1 year ago
7 0

Answer: 8x^6 y^3

Step-by-step explanation:

See attached image.

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A candy machine can make 25.15 pounds of candy in an hour. How much candy can it make in 6.5 hours?
xxMikexx [17]

Answer:

i believe its 163.475 pounds of candy

Step-by-step explanation:

i multiplied 25.15 by 6.5

8 0
2 years ago
Read 2 more answers
In a sample of 150 cars, 18 cars failed a safety inspection. The sampling method had a margin of error of 0.02
mestny [16]

Answer:  

(Lower limit, Upper limit) = (0.10, 0.14)

(Lower limit, Upper limit) = (10%, 14%)

Step-by-step explanation:  

Total number of cars = 150

Cars that failed the safety inspection = 18

The proportion is given by

p = 18/150

p = 0.12

p = 12%

The confidence interval is given by

p ± margin of error

Where margin of error is 0.02

0.12 ± 0.02

Lower limit = 0.12 - 0.02

Lower limit = 0.10

Lower limit = 10%

Upper limit = 0.12 + 0.02

Upper limit = 0.14

Upper limit = 14%

(Lower limit, Upper limit) = (0.10, 0.14)

(Lower limit, Upper limit) = (10%, 14%)

7 0
2 years ago
Can someone please explain how to solve this? And give me the answer?! THANK U !
Lyrx [107]

we know the segment QP is an angle bisector, namely it divides ∡SQR into two equal angles, thus ∡1 = ∡2, and ∡SQR = ∡1 + ∡2.

\bf \begin{cases} \measuredangle SQR = \measuredangle 1 + \measuredangle 2\\\\ \measuredangle 2 = \measuredangle 1 = 5x-7 \end{cases}\qquad \qquad \stackrel{\measuredangle SQR}{7x+13} = (\stackrel{\measuredangle 1}{5x-7})+(\stackrel{\measuredangle 2}{5x-7}) \\\\\\ 7x+13 = 10x-14\implies 13=3x-14\implies 27=3x \\\\\\ \cfrac{27}{3}=x\implies 9=x \\\\[-0.35em] ~\dotfill\\\\ \measuredangle SQR = 7(9)+13\implies \measuredangle SQR = 76

4 0
3 years ago
How much money has to be invested at 5.9% interest compounded continuously to have $15,000 after 12 years?
scoray [572]

The amount of $7389.43 has to be invested at 5.9% interested continuously to have $15,000 after 12 years.

Step-by-step explanation:

The given is,

                Future value, F  = $15,000

                           Interest, i = 5.9%

              ( compounded continuously )

                            Period, t = 12 years

Step:1

           Formula to calculate the present with compounded continuously,

                                       F=Pe^{(i)(t)}...............(1)

           Substitute the values in equation (1) to find the P value,

                                  15000=Pe^{(0.059)(12)}          ( ∵ i = \frac{5.9}{100}=0.059 )

                                  15000=Pe^{0.708}

                                  15000=P(2.0299)             ( ∵ e^{o.708} =2.0299 )

            We change the P (Present value) into the left side,

                                        P=\frac{15000}{2.0299}

                                            =7389.427

                                            ≅ 7389.43

                                         P = $ 7389.43

Result:

           The amount of $7389.43 has to be invested at 5.9% interested continuously to have $15,000 after 12 years.  

                       

8 0
3 years ago
Expand: f(x)= x^4- x^3+x^2+x-
emmainna [20.7K]
F(x) = x (x^3 - x^2 + x + 1)

6 0
2 years ago
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