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2 years ago

13. Which equation defines the graph of y = x^2 after it is shifted vertically 3 units up and horizontally 2 units right?

2 answers:

8 0

The three units upward shift is denoted by +3 outside of the parenthesis and horizontal shift to the right is represented by -2 inside the parenthesis.
The answer is C.

andreyandreev [35.5K]2 years ago

7 0

The graph of y = x² ( the parent function ) is shifted vertically 3 units up and horizontally 2 units right:
y = ( x - h )² + k, where: h = 2 and k = 3
Answer:
C ) y = ( x - 2 )² + 3

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How many terms are in the following sequence? 131072, ..., 8, 4, 2

Klio2033 [76]

Answer:

17 terms

Step-by-step explanation:

131072 = 2^17

8 = 2^3

4 = 2^2

2 = 2^1

Apparently, the sequence is powers of 2 from 17 down to 1, so there are 17 terms in the sequence.

8 0

2 years ago

Write the equation in slope-intercept form of the line that has a slope of -2 and y-intercept of 2.

bixtya [17]

Answer:

y= -2x +2

Step-by-step explanation:

Slope-intercept form:

y= mx +c, where m is the slope and c is the y-intercept.

Given that the slope is -2, m= -2.

Substitute m= -2 into the equation:

y= -2x +c

Given that the y-intercept is 2, c= 2.

Substitute c=2 into the equation:

y= -2x +2

8 0

2 years ago

A Norman window is a window with a semi-circle on top of regular rectangular window. (See the picture.) What should be the dimen

Vikki [24]

Answer:

bottom side (a) = 3.36 ft

lateral side (b) = 4.68 ft

Step-by-step explanation:

We have to maximize the area of the window, subject to a constraint in the perimeter of the window.

If we defined a as the bottom side, and b as the lateral side, we have the area defined as:

$A=A_r+A_c/2=a\cdot b+\dfrac{\pi r^2}{2}=ab+\dfrac{\pi}{2}\left (\dfrac{a}{2}\right)^2=ab+\dfrac{\pi a^2}{8}$

The restriction is that the perimeter have to be 12 ft at most:

$P=(a+2b)+\dfrac{\pi a}{2}=2b+a+(\dfrac{\pi}{2}) a=2b+(1+\dfrac{\pi}{2})a=12$

We can express b in function of a as:

$2b+(1+\dfrac{\pi}{2})a=12\\\\\\2b=12-(1+\dfrac{\pi}{2})a\\\\\\b=6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a$

Then, the area become:

$A=ab+\dfrac{\pi a^2}{8}=a(6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a)+\dfrac{\pi a^2}{8}\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a^2+\dfrac{\pi a^2}{8}\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{4}-\dfrac{\pi}{8}\right)a^2\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{8}\right)a^2$

To maximize the area, we derive and equal to zero:

$\dfrac{dA}{da}=6-2\left(\dfrac{1}{2}+\dfrac{\pi}{8}\right )a=0\\\\\\6-(1-\pi/4)a=0\\\\a=\dfrac{6}{(1+\pi/4)}\approx6/1.78\approx 3.36$

Then, b is:

$b=6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a\\\\\\b=6-0.393*3.36=6-1.32\\\\b=4.68$

3 0

2 years ago

25. Michael is studying population changes in two

g100num [7]

Answer: Average rates of change for Bird A is 0.045 and for Bird B is 3.816.

Step-by-step explanation: Through its graph, a function can be analyzed and be identified its attributes. Average Rate of Change is the ratio of change in the function values to the change of x-value, i.e., it is the slope of the function in a specific interval of x. With the Average it is possible to compare two function.

Average Rate of Change

Bird A:

For the interval [0,18]:

x₁ = 0 f(0) = 8.3

x₂ = 18 f(18) = 9.1

Average = $\frac{f(18) - f(0)}{x_{2} - x_{1} }$

Average = $\frac{9.1 - 8.3}{18 - 0}$

Average = 0.045

Bird B: y = 3.6(1.06)x

For the interval [0,18]:

x₁ = 0 y = 3.6(1.06)0 = 0

x₂ = 18 y = 3.6(1.06)18 = 68.7

Average = $\frac{f(18) - f(0)}{x_{2} - x_{1} }$

Average = $\frac{68.7 - 0}{18 - 0}$

Average = 3.816

The Average Rate for Change for Bird A is 0.045 and for Bird B is 3.816. This means that the population of Bird B increase in rate faster than the population of Bird A.

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2 years ago

the code contains four digits to the right of the decimal, the digit in the hundreds place, the digit in the tenths place is an

grigory [225]

to hi hello how to help you out front of your house at the

4 0

2 years ago