What is the range of the function f(x)=(x-4)^2-5
2 answers:
The answer to this question is a
f(x) = (x - 4)^2 - 5
Vertex (4 , -5)
This function opens upward and has min. value = -5
So range y >= - 5
So answer is A. -5 <= f(x) < ∞
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