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netineya [11]
2 years ago
5

What is the range of the function f(x)=(x-4)^2-5

Mathematics
2 answers:
Ksivusya [100]2 years ago
5 0
The answer to this question is a
uranmaximum [27]2 years ago
4 0

f(x) = (x - 4)^2 - 5

Vertex (4 , -5)

This function opens upward and has min. value = -5

So range y >=  - 5

So answer is A. -5 <= f(x) < ∞

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