3 years ago

What is the range of the function f(x)=(x-4)^2-5

Mathematics

2 answers:

Ksivusya [100]3 years ago

5 0

The answer to this question is a

uranmaximum [27]3 years ago

4 0

f(x) = (x - 4)^2 - 5

Vertex (4 , -5)

This function opens upward and has min. value = -5

So range y >= - 5

So answer is A. -5 <= f(x) < ∞

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Solve for substitution 8x+2y=13 and 4x+y=11

damaskus [11]

Solving for X:
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