Question

What is the range of the function f(x)=(x-4)^2-5

Answer 1

The answer to this question is a

Answer 2

f(x) = (x - 4)^2 - 5

Vertex (4 , -5)

This function opens upward and has min. value = -5

So range y >=  - 5

So answer is A. -5 <= f(x) < ∞