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Airida [17]
2 years ago
12

HELP PLEASE factor completely. 25d^8−80d^4+64=

Mathematics
1 answer:
Dominik [7]2 years ago
8 0

Answer:

(5d⁴ − 8)²

Step-by-step explanation:

I hope this is helpful!

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Assume that y varies inversely with x. If y = 7 when x = 2/3, find y when x = 7/3. <br>y = [?] ​
Alekssandra [29.7K]

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y = 2

Step-by-step explanation:

varies inversely

xy = k

y = 7 when x = 2/3

(2/3)7 = k

14/3 = k

k = 14/3

--------------------

find y when x = 7/3

(7/3)y = 14/3

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What is the difference between an irrational number and an integer? (PLZ HELP ME ANSWER ASAP!!!! All help is appreciated! :D)
enot [183]
So, first off it would help if you could define the terms irrational number and integer. Well, an irrational number is basically any real number that can't be expressed as a ratio of integers. They also cannot be represented by terminating or continuing decimals. And an integer is pretty much any number that cannot be written as a fraction or decimal, such as -2, 13, 257. It is not 2 and 1/2, or 4.75. Those would not be integers. Do you think you can figure out the difference?

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3 years ago
A random sample of 102 full-grown lobsters had a mean weight of 16 ounces and a standard deviation of 3.4 ounces. Construct a 98
pshichka [43]

Answer:

The best point estimate for a confidence interval estimating the population μ is 16 ounces.

The 98 percent confidence interval for the population mean μ is between 15.21 ounces and 16.79 ounces.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The best point estimate for a confidence interval estimating the population μ is

The sample mean, so 16 ounces.

T interval

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 102 - 1 = 101

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 101 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.98}{2} = 0.99. So we have T = 2.36

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.36\frac{3.4}{\sqrt{102}} = 0.79

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 16 - 0.79 = 15.21 ounces

The upper end of the interval is the sample mean added to M. So it is 16 + 0.79 = 16.79 ounces

The 98 percent confidence interval for the population mean μ is between 15.21 ounces and 16.79 ounces.

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